我正在尝试抓取我作为学习实验编写的文件。看起来像这样:
<div class="container">
<div class="date">1st</div>
<div class="events">
<div class="meeting">
<span class="name">Bob</span>
</div>
</div>
<div class="date">2nd</div>
<div class="event">
<div class="meeting">
<span class="name">Emma</span>
<span class="name">Frank</span>
<span class="name">Charlie</span>
</div>
</div>
<div class="date">3rd</div>
<div class="event">
<div class="meeting">
<span class="name">Lisa</span>
<span class="name">Tony</span>
</div>
</div>
</div>
我想抓取数据,以便它返回具有关联日期的Span。例如:
data = [['1st', 'bob'], ['2nd', 'Emma', 'Frank' 'Charlie'], ['3rd', 'Lisa', 'Tony']]
我遇到的问题是,当我使用以下内容进行抓取时,Div的date
和event
处于同一级别:
for data in schedule_soup.find_all('div', 'container'):
for date in data.find_all('div', 'date'):
print(date)
for name in data.find_all('span', 'name'):
print(name)
我明白了:
<div class="date">1st</div>
<div class="date">2nd</div>
<div class="date">3rd</div>
<span class="name">Bob</span>
<span class="name">Emma</span>
<span class="name">Frank</span>
<span class="name">Charlie</span>
<span class="name">Lisa</span>
<span class="name">Tony</span>
答案 0 :(得分:1)
尝试使用下面的代码,它对我有用
final_list=[]
dates = soup.find_all('div', 'date')
for c in range(len(dates)):
temp_list=[]
temp_list.append(dates[c].text)
meeting = soup.find_all('div', 'meeting')
meeting = BeautifulSoup(str(meeting[c]),'html.parser')
for name in meeting.find_all('span','name'):
temp_list.append(name.text)
final_list.append(temp_list)
print(final_list)
[[''stst','Bob'],['2nd','Emma','Frank','Charlie'],['3rd','Lisa','Tony']]
答案 1 :(得分:0)
您可以使用zip功能:
final_list=[]
dates = soup.find_all('div', 'date')
meetings = soup.find_all('div', 'meeting')
for date1, meeting in zip(dates, meetings):
temp_list=[]
temp_list.append(date1.text)
[temp_list.append(x.text) for x in meeting.find_all('span')]
final_list.append(temp_list)
print (final_list)