Question

基于Table_1中一列的值（COLUMN_NAME），我想在Table_2中插入3条新记录。最好的方法是什么？我已经尝试过如下操作，但我不想使用UNION ALL

使用三个查询

SQL> DROP TABLE TABLE_2
Table dropped.
SQL> CREATE TABLE TABLE_2(EMP_ID VARCHAR2(10),VALUE VARCHAR2(10))
Table created.
SQL> TRUNCATE TABLE TABLE_2
Table truncated.
SQL> INSERT INTO TABLE_2
(EMP_ID,VALUE)
WITH TABLE_1 as 
(
    SELECT '111' AS EMP_ID,'COL1' COLUMN_NAME FROM DUAL
)
SELECT EMP_ID,CASE WHEN COLUMN_NAME = 'COL1' THEN 'RICK' END AS VALUE  
FROM TABLE_1
UNION ALL
SELECT EMP_ID,CASE WHEN COLUMN_NAME = 'COL1' THEN 'TOM' END AS VALUE  
FROM TABLE_1
UNION ALL
SELECT EMP_ID,CASE WHEN COLUMN_NAME = 'COL1' THEN 'ADAM' END AS VALUE  
FROM TABLE_1
COMMIT
3 rows created.
SQL> SELECT * FROM TABLE_2

EMP_ID     VALUE     
---------- ----------
111        RICK      
111        TOM       
111        ADAM      

3 rows selected.

Answer 1

您可以使用INSERT ALL：

INSERT ALL 
  INTO TABLE_2(EMP_ID,VALUE) VALUES (EMP_ID, 'Rick')
  INTO TABLE_2(EMP_ID,VALUE) VALUES (EMP_ID, 'Tom')
  INTO TABLE_2(EMP_ID,VALUE) VALUES (EMP_ID, 'Adam')
SELECT '111' AS EMP_ID,'COL1' COLUMN_NAME FROM DUAL;

db<>fiddle demo

ORACLE：基于单个列值插入多个记录

1 个答案: