我目前有一个With语句,它将一个单元格的值与一系列单元格进行比较,并且InStr()
返回true,然后将cell.Value
标记为“ Yes"
”,否则将{{ 1}}。
这是场景。假设我正在检查"No"
的值,它是A2
。我正在将111
与一系列其他单元格进行比较,并且应该匹配的字段为111
,因为其中包含111, 222, 333
。我下面的第一组代码对此有效,但是速度很慢。我希望有一个更快的方法,我认为我可以使用公式来做到这一点,但是在vlookup中使用111
而不是True
却无法正常工作。
代码如下:
False
问题在于它有点慢。我的应用程序大约需要5分钟才能运行。我希望将With inv_twcg_ws
For Each cell In .Range("A2:A" & .Cells(Rows.Count, "A").End(xlUp).Row)
For Each cellx In report_rng
If InStr(cellx.Value, cell.Value) Then
cell.Offset(0, 6).Value = "Yes"
Exit For
End If
cell.Offset(0, 6).Value = "No"
Next cellx
Next cell
End With
与InStr()
结合起来以尝试加快公式的速度。这可能吗?
这是我当前的Vlookup,但是使用Application.Vlookup()
并不能满足我的需要...
True
答案 0 :(得分:6)
使用变量数组:
Dim report_ws As Worksheet
Set report_ws = report_wb.Worksheets(1)
Dim report_rng As Variant
report_rng = report_ws.Range("B2:B" & last_row)
Dim inv_twcg_ws As Worksheet
Set inv_twcg_ws = Worksheets("Sheet1") ' change to your sheet
With inv_twcg_ws
Dim lkup_rng As Variant
lkup_rng = .Range("A2:A" & .Cells(Rows.Count, "A").End(xlUp).Row).Value
Dim otpt As Variant
ReDim otpt(1 To UBound(lkup_rng, 1), 1 To 1) As Variant
Dim i As Long
For i = LBound(lkup_rng, 1) To UBound(lkup_rng, 1)
otpt(i,1) = "No"
Dim j As Long
For j = LBound(report_rng, 1) To UBound(report_rng, 1)
If InStr(report_rng(j, 1), lkup_rng(i, 1)) Then
otpt(i,1) = "Yes"
Exit For
End If
Next j
Next i
.Range("G2").Resize(UBound(otpt, 1)).Value = otpt
End With