Question

我当前的echo $sql;返回两个查询：

UPDATE 00001 SET discount=11, discount_price=166.43, discount_price=166.00 WHERE code=00001070170UPDATE 00001 SET discount=11, discount_price=166.43, discount_price=166.00 WHERE code=00001070171

我想知道如何将它们分开并添加;在每个结尾处。我的$ sql命令如下：

$sql = ("UPDATE ".$row['sku']." SET discount=".$discount1.", discount_price=".$discount_price1.", discount_price_elite=".$discount_price." WHERE code=".$row['code']."");

预期的输出是：

UPDATE 00001 SET discount=11, discount_price=166.43, discount_price=166.00 WHERE code=00001070170;
UPDATE 00001 SET discount=11, discount_price=166.43, discount_price=166.00 WHERE code=00001070171

Answer 1

不要尝试将它们合并为一个查询，而是将它们作为单独的查询进行：

foreach ($rows as $row) {
    $sql = "UPDATE ".$row['sku']." SET discount=".$discount1.", discount_price=".$discount_price1.", discount_price_elite=".$discount_price." WHERE code=".$row['code'];
    mysqli_query($mysqli, $sql);
}

顺便说一句，对于每个SKU都有一个单独的表是一个非常奇怪的数据库设计。通常应该只有一个products表和一个sku列。

多个SQL输出

1 个答案: