Question

我正在尝试将图像从本地系统上传到Azure中的Blob存储。我要获取图像名称，但是如何获取所选图像的完整路径？

这就是我所做的：

class Uploadfile @Inject() (implicit val messagesApi: MessagesApi, ec: ExecutionContext) extends Controller with i18n.I18nSupport
{


  var path="";
  val dbConfig = Database.forURL("jdbc:mysql://localhost:3306/equineapp?user=root&password=123456", driver = "com.mysql.jdbc.Driver")

  def upload(HorseId : Int) = Action(parse.multipartFormData) { request =>
    request.body.file("picture").map { picture =>

      val filename = Paths.get(picture.filename).getFileName  /// from here i am geeting Image name
      var connString="DefaultEndpointsProtocol=https;AccountName=XXXXXXXXXXXXX;AccountKey=XXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXX==;EndpointSuffix=core.windows.net";
      val account = CloudStorageAccount.parse(connString)
      val serviceClient = account.createCloudBlobClient

      // Container name must be lower case.
      val container = serviceClient.getContainerReference("myimages")
      container.createIfNotExists

      // Upload an image file.s
      val blob = container.getBlockBlobReference(filename.toString())
//var path =filename.getRoot

      //def absolutePath: String = new File(filename).getAbsolutePath();


     var pathimage=filename.getFileSystem//// how to get full path of selected Image









      val sourceFile = new File(pathimage.toString())
      blob.upload(new FileInputStream(sourceFile), sourceFile.length)




//      val setup1 =  sql"call horseimagepath ($HorseId, $path);".as[(String)]
//      val res = Await.result(dbConfig.run(setup1), 1000 seconds)

      Ok("File uploaded"+filename+ sourceFile)


    }.getOrElse {
      Redirect(routes.HomeController.index()).flashing(
        "error" -> "Missing file")
    }
  }


}

如果我对图像的完整路径进行硬编码，那么我没有得到任何例外，但是如何动态获取图像的完整路径？

使用Scala Play2.6将图片上传到Azure中的Blob容器

0 个答案: