删除实时数据库-Firebase

时间:2018-09-17 11:19:05

标签: javascript database firebase firebase-realtime-database firebase-security-rules

我正在使用Firebase实时数据库,并为数据库设置了以下规则,

{
  "rules": {
    ".read": "auth !== null",
    ".write": "auth !== null"
  }
}

但是当我尝试删除一个条目时,它给我一个错误,指出权限被拒绝,如下所示。

Database: Client doesn't have permission to access the desired data. (database/permission-denied).

我该怎么办?我不明白为什么我可以使用当前规则进行所有读写操作而不删除。

有人可以帮我吗?

注意: 与Firebase Simulator相关的结果图像

enter image description here

当检查firebase.auth().currentUser时:

deleteUserAccount(userId) {
 let knownLocationRef = this.database.ref('lastKnown/' + userId);
 let promises = [];
 console.log('auth details', this.auth.currentUser);
 console.log('auth details null', this.auth.currentUser !== null); //returns true
         knownLocationRef.once('value').then( (data) => {
            console.log('data ', data.val());
            if (data.val() !== null) {
                let prevLat = data.val().lat;
                let prevLong = data.val().long;
                console.log('auth details', this.auth.currentUser);
                console.log('auth details null', this.auth.currentUser !== null); //returns false
                promises.push(knownLocationRef.remove());
            }
        });
         return Promise.all(promises);
 }

1 个答案:

答案 0 :(得分:0)

以下是您的代码以及如何处理承诺的一些问题:

function deleteUserAccount(userId) {
  let knownLocationRef = this.database.ref('lastKnown/' + userId);
  let promises = []; // good idea for collecting a list of distinct 
                     // promises, maybe not here

  // This is a promise, 'then' is a continuation from which you can return 
  // either a data result or another promise
  knownLocationRef.once('value').then((data) => {
    // if data is valid, return another promise
    if (data.val() !== null) {
      // ...

      // If you were looping and collecting promises, then this might help, 
      // but you don't want to collect inner promises.
      promises.push(knownLocationRef.remove());
    }
  });

  // This returns before everything in `.then` executes
  return Promise.all(promises);
}

这是固定版本:

function deleteUserAccount(userId) {
  let knownLocationRef = this.database.ref('lastKnown/' + userId);
  let promises = []; // For the sake of argument, I will use this to collect 
                     // outer promises.

  // normally I would return here, but as an example, I'll uses the 
  // promises array
  promises.push(knownLocationRef.once('value').then((data) => {
    // if data is valid, return another promise
    if (data.val() !== null) {
      // ...

      // Return a Promise from a promise
      return knownLocationRef.remove();
    }

    return null; // no data to process
  }));

  // wait on outer promises
  return Promise.all(promises)
    .catch(console.log); // log errors from any promise
}

这是一个没有额外的promises数组的版本。

function deleteUserAccount(userId) {
  let knownLocationRef = this.database.ref('lastKnown/' + userId);

  return knownLocationRef.once('value')
    .then((data) => {
      // if data is valid, return another promise
      if (data.val() !== null) {

        // Return a Promise from a promise
        return knownLocationRef.remove();
      }

      return null; // no data to process
    })
    .catch(console.log);
}