所以我有一些看起来像这样的HTML:
<div class="spinning-items">
<div>
<ul>
<li>
Hello, How Are You?
</li>
</ul>
</div>
</div>
我需要删除“ spinning-items”-div中的所有元素,但要保留其内容。在这种情况下,“你好,你好吗?”。 所以,我希望它以后看起来像这样:
<div class="spinning-items">
Hello, How Are You?
</div>
任何人都可以向我指出正确的方向,或者为我提供可行的解决方案吗?
谢谢。
答案 0 :(得分:6)
尝试关注
$(".spinning-items").html($(".spinning-items").text().trim())
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="spinning-items">
<div>
<ul>
<li>
Hello, How Are You?
</li>
</ul>
</div>
</div>
如果类spinning-items
中有1个以上元素
$(".spinning-items").each((i,e) => $(e).html($(e).text().trim()))
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="spinning-items">
<div>
<ul>
<li>
Hello, How Are You?
</li>
</ul>
</div>
</div>
<div class="spinning-items">
<div>
<ul>
<li>
Hello, How Are You Doing?
</li>
</ul>
</div>
</div>
答案 1 :(得分:1)
使用本地javascript,您可以使用regex和trim()删除空白
let k = document.getElementsByClassName('spinning-items')[0].innerHTML;
var rex = /(<([^>]+)>)/ig;
document.getElementsByClassName('spinning-items')[0].innerHTML = k.replace(rex, "").trim();
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="spinning-items">
<div>
<ul>
<li>
Hello, How Are You?
</li>
</ul>
</div>
</div>
答案 2 :(得分:0)
$(".spinning-items"")
.clone() //clone the element
.children() //select all the children
.remove() //remove all the children
.end() //again go back to selected element
.text(); //get the text of element
这只会给您文本