Question

我正在尝试处理生产者和消费者的简单RabbitMQ实例。

public void newCustomerToQueue(Custom custom) throws Exception{

    ConnectionFactory factory = new ConnectionFactory();
    factory.setHost("localhost");
    Connection connection = factory.newConnection();
    Channel channel = connection.createChannel();

    channel.queueDeclare(TASK_QUEUE_NAME, true, false, false, null);
    CustomWrap custom= new CustomWrap();
    custom.setname(custom.getname());

    String jsonString;
    try {
        jsonString = new ObjectMapper().writeValueAsString(custom);
       // System.out.println(jsonString);
    } catch (IOException e) {
        throw new RuntimeException(e); //todo
    }


    try {
        channel.basicPublish("",TASK_QUEUE_NAME, null, SerializationUtils.serialize(jsonString));
    } catch (IOException e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
    }
    System.out.println(" [x] Sent '" + jsonString + "'");     
}

我的接班人如下：

public void ReceiveLead() throws Exception{

    final String TASK_QUEUE_NAME = "task_queue";
    ConnectionFactory factory = new ConnectionFactory();
    factory.setHost("localhost");
    final com.rabbitmq.client.Connection connection = factory.newConnection();
    final Channel channel = connection.createChannel();

    channel.queueDeclare(TASK_QUEUE_NAME, true, false, false, null);
    System.out.println(" [*] Waiting for messages. To exit press CTRL+C");
    channel.basicQos(1);

    final Consumer consumer = new DefaultConsumer(channel) {

        @Override
        public void handleDelivery(String consumerTag, Envelope envelope, AMQP.BasicProperties properties, byte[] body) throws IOException {

            String message = new String(body, "UTF-8");
            System.out.println("Recieved" +message);

            try {
              byte[] body1 = message.getBytes();
              System.out.println("inside"+new String(body1));

            doWork(body1);

            } catch (JSONException e) {
                // TODO Auto-generated catch block
                e.printStackTrace();
            } finally {
                System.out.println(" [x] Done");
                channel.basicAck(envelope.getDeliveryTag(), false);
            }          
        }
    };

    channel.basicConsume(TASK_QUEUE_NAME, false, consumer);   

}

问题是当我收到此特定消息时，我的字符串中将附加字符，例如：收到了'?? t = {“名称”：“字符串”}' 有人可以帮帮我吗，我似乎找不到原因了！

Answer 1

带有有效负载的字符串应使用UTF-8编码转换为字节数组：

jsonString.getBytes(Charset.forName("UTF-8"));

在这种情况下，不应使用SerializationUtils.serialize，因为它会添加有关序列化对象的其他元数据。

在Rabbitmq消息中添加了多余的字符

1 个答案: