根据标题,SQL Mongo等同于SQL中的内容:
SELECT DISTINCT(field) FROM table WHERE someCondition = 1
我看了this table,但我没看到如何将db.users.distinct('last_name')
映射到PHP。
答案 0 :(得分:4)
只需发出command并设置distinct
密钥。
从文档中查看以下示例:
查找密钥的所有不同值。
<?php
$people = $db->people;
$people->insert(array("name" => "Joe", "age" => 4));
$people->insert(array("name" => "Sally", "age" => 22));
$people->insert(array("name" => "Dave", "age" => 22));
$people->insert(array("name" => "Molly", "age" => 87));
$ages = $db->command(array("distinct" => "people", "key" => "age"));
foreach ($ages['values'] as $age) {
echo "$age\n";
}
?>
以上示例将输出类似于:
的内容4
22
87
答案 1 :(得分:4)
如果需要添加where子句,请使用以下语法:
$ages = $db->command(array(
"distinct" => "people",
"key" => "age",
"query" => array("someField" => "someValue")));