Question

如果client.wait_for_message超时，我正在尝试发送消息。在这种情况下为30秒。我使用了TimeoutError，但它不会引发任何错误或无法正常工作。

 try:
    msg = await client.wait_for_message(timeout= 30, author=message.author, check=check)
        if msg:
            await client.send_message(message.channel, "Nice job! {} solved the scramble! The word was {}!".format(message.author.mention, word))
    except TimeoutError:
        await client.send_message(message.channel, "Oops! Nobody solved it. The word was {}!".format(word))

Answer 1

import asyncio

try:
    msg = await client.wait_for_message(timeout= 30, author=message.author, check=check)
    if msg:
        await client.send_message(message.channel, "message")
except asyncio.TimeoutError:
    await client.send_message(message.channel, "message")

你的缩进是错误的，你的声明也是应该是 asyncio.TimeoutError

抱歉回复了 2 年的帖子

Answer 2

很抱歉，经过研究，我想出了以下解决方案：

     msg = await client.wait_for_message(timeout= 30, author=message.author, check=check)
        if msg:
            await client.send_message(message.channel, "Nice job! {} solved the scramble! The word was {}!".format(message.author.mention, word))
        elif msg is None:
            await client.send_message(message.channel, "Oops! Nobody solved it. The word was {}!".format(word))

如果达到Wait_For_Message超时，则发送消息

2 个答案: