Question

我是编程的新手，这让我绊了脚，我一直在想做这样的事情，但我做不到

num1 = int(input('What is the first number?:'))
num2 = int(input('What is the second number?:'))
num3 = int(input('What is the third number?:'))

[[[此后，我开始思考elif语句并使用[and，or]]

Answer 1

将所有variables添加到list中，然后您就可以像这样max那样使用max(lista)函数

num1 = int(input('What is the first number?: '))
num2 = int(input('What is the second number?: '))
num3 = int(input('What is the third number?: '))

lista = [num1, num2, num3]

biggest = max(lista)

print(f"{biggest} is the largest value.")

(xenial)vash@localhost:~/python/stack_overflow$ python3.7 max.py
What is the first number?: 10
What is the second number?: 3
What is the third number?: 8
10 is the largest value.

仅需一点奖励，它不包括处理TypeErrors，但想给您一些想法，让您可以在这个小项目中进行尝试：

while True:

    numbers = int(input("How many numbers would you like to enter: "))

    values = []

    for i in range(numbers):
        if i == numbers - 1:
            values.append(int(input(f"Enter 1 number: ")))
        else:
            values.append(int(input(f"Enter {numbers - i} numbers: ")))

    print(f"\nThe largest number entered was {max(values)}")

(xenial)vash@localhost:~/python/stack_overflow$ python3.7 max.py
How many numbers would you like to enter: 5
Enter 5 numbers: 10
Enter 4 numbers: 8
Enter 3 numbers: 29
Enter 2 numbers: 13
Enter 1 number: 22

The largest number entered was 29

Answer 2

Python的max（list）为您完成工作。

如果您希望创建一个可以接受任意数量输入的函数，则可以创建这样的函数。

def my_function(*args):
    return max(args)

Answer 3

num1=int(input('What is the first number?:'))
num2=int(input('What is the second number?:'))
num3=int(input('What is the third number?:'))
if(num1>num2 and num1>num2):
    print(num2, 'is the largest value')
elif(num2>num1 and num2>num3):
    print(num2, 'is the largest value')
else:
    print(num3, 'isenter code here the largest value')

如何在不使用循环的情况下找到（三个值）的最大值？ [蟒蛇]

3 个答案: