我已经添加了一个脚本,该脚本使用ES6传播运算符到从URL获取参数的项目中。我发现该项目不支持ES6后,不确定如何将其恢复为普通的Javascript语法。
采用普通的Javascript数组并使用传播运算符很容易,但是在像这样的更复杂的实例中,如果不完全更改脚本,我无法使数组返回结果。
getQueryURLParams("country");
getQueryURLParams = function(pName) {
var urlObject = location.search
.slice(1)
.split('&')
.map(p => p.split('='))
.reduce((obj, pair) => {
const [key, value] = pair.map(decodeURIComponent);
return ({ ...obj, [key]: value }) //This is the section that needs to be Vanilla Javascript
}, {});
return urlObject[pName];
};
感谢大家的答复。来回往复之后,我意识到我将整个脚本转换为ES5的建议是正确的,因为浏览器仅抱怨该行,而其他项目(非ES5)也存在问题。
这是我使用ES5之后的经历:
getQueryURLParams = function(pName) {
if (typeof Object.assign != 'function') {
// Must be writable: true, enumerable: false, configurable: true
Object.defineProperty(Object, "assign", {
value: function assign(target, varArgs) { // .length of function is 2
'use strict';
if (target == null) { // TypeError if undefined or null
throw new TypeError('Cannot convert undefined or null to object');
}
var to = Object(target);
for (var index = 1; index < arguments.length; index++) {
var nextSource = arguments[index];
if (nextSource != null) { // Skip over if undefined or null
for (var nextKey in nextSource) {
// Avoid bugs when hasOwnProperty is shadowed
if (Object.prototype.hasOwnProperty.call(nextSource, nextKey)) {
to[nextKey] = nextSource[nextKey];
}
}
}
}
return to;
},
writable: true,
configurable: true
});
}
var urlObject = location.search
.slice(1)
.split('&')
.map(function(element ) {
return element.split('=');
})
.reduce(function(obj, pair) {
const key = pair.map(decodeURIComponent)[0];
const value = pair.map(decodeURIComponent)[1];
return Object.assign({}, obj, { [key]: value });
}, {});
return urlObject[pName];
};
答案 0 :(得分:8)
您可以使用Object.assign()
:
return Object.assign({}, obj, { [key]: value });
演示:
const obj = { a: 1 };
const key = 'b';
const value = 2;
console.log(Object.assign({}, obj, { [key]: value }));
FWIW,{ ...obj }
语法称为“ Object Rest/Spread Properties”,它是ECMAScript 2018的一部分,而不是ECMAScript 6。
答案 1 :(得分:2)
因为您要使用ES5
的语法,所以这里是Object.assing()
(source: MDN)的polyfill
// we first set the Object.assign function to null to show that the polyfill works
Object.assign = null;
// start polyfill
if (typeof Object.assign != 'function') {
// Must be writable: true, enumerable: false, configurable: true
Object.defineProperty(Object, "assign", {
value: function assign(target, varArgs) { // .length of function is 2
'use strict';
if (target == null) { // TypeError if undefined or null
throw new TypeError('Cannot convert undefined or null to object');
}
var to = Object(target);
for (var index = 1; index < arguments.length; index++) {
var nextSource = arguments[index];
if (nextSource != null) { // Skip over if undefined or null
for (var nextKey in nextSource) {
// Avoid bugs when hasOwnProperty is shadowed
if (Object.prototype.hasOwnProperty.call(nextSource, nextKey)) {
to[nextKey] = nextSource[nextKey];
}
}
}
}
return to;
},
writable: true,
configurable: true
});
}
// end polyfill
// example, to test the polyfill:
const object1 = {
a: 1,
b: 2,
c: 3
};
const object2 = Object.assign({c: 4, d: 5}, object1);
console.log(object2.c, object2.d);
// expected output: 3 5