Question

我使用球衣和弹簧靴创建了一个API。现在，当我在请求正文中使用Postman命中POST请求时：

{
     "name":"something", "email":"something","location":"something","dateOfBirth":"something"
}

有效。保存此数据的功能是：

@POST
@Path("/addEmployee")
    @Produces(MediaType.TEXT_PLAIN)
    public String addEmployee(@RequestBody Employee employee) {
        service.save(employee);
        return "Saved Successfully";
    }

员工模型为：

@Entity
@Table(name = "employee")
@XmlRootElement(name = "employee")
@EntityListeners(AuditingEntityListener.class)
public class Employee {
    public Employee() {
    }
    @Id
    @Column(nullable = false, name = "id")
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    private Long id;

    @Column(nullable = false, name = "name")
    private String name;

    @Column(nullable = false, name = "email")
    private String email;

    @Column(nullable = false, name = "location")
    private String location;

    @Column(nullable = false, name = "DOB")
    private String dateOfBirth;

    // getters and setters

此api由客户端的以下功能调用：

@RequestMapping(value = "/addEmployee", method = RequestMethod.GET)
    public ModelAndView addEmployee(ModelAndView model) {

        RestTemplate restTemplate = new RestTemplate();
        String url = "http://localhost:8080/api/addEmployee";

        EmployeeInfo employee = new EmployeeInfo();
        employee.setName("Ashish");
        employee.setEmail("anyhing");
        employee.setDateOfBirth("mybirthday");
        employee.setLocation("home");
        ResponseEntity<String> response = restTemplate.postForEntity(url, employee, String.class);

        model.setViewName("homePage");
        return model;
    }

员工信息类别为：

public class EmployeeInfo {

    private String name;

    private String email;

    private String location;
    public String getName() {
        return name;
    }
    public void setName(String name) {
        this.name = name;
    }
    public String getEmail() {
        return email;
    }

我遇到的错误是：

  2018-09-16 15:57:13.706 ERROR 14892 --- [nio-8080-exec-1] o.a.c.c.C.[.[.[/].[dispatcherServlet]    : Servlet.service() for servlet [dispatcherServlet] in context with path [] threw exception [Request processing failed; nested exception is org.springframework.web.client.HttpClientErrorException: 404 null] with root cause

org.springframework.web.client.HttpClientErrorException: 404 null
    at org.springframework.web.client.DefaultResponseErrorHandler.handleError(DefaultResponseErrorHandler.java:86) ~[spring-web-4.3.19.RELEASE.jar:4.3.19.RELEASE]
    at org.springframework.web.client.RestTemplate.handleResponse(RestTemplate.java:708) ~[spring-web-4.3.19.RELEASE.jar:4.3.19.RELEASE]
    at org.springframework.web.client.RestTemplate.doExecute(RestTemplate.java:661) ~[spring-web-4.3.19.RELEASE.jar:4.3.19.RELEASE]
    at org.springframework.web.client.RestTemplate.execute(RestTemplate.java:621) ~[spring-web-4.3.19.RELEASE.jar:4.3.19.RELEASE]
    at org.springframework.web.client.RestTemplate.postForEntity(RestTemplate.java:415) ~[spring-web-4.3.19.RELEASE.jar:4.3.19.RELEASE]
    at com.example.controller.Home.addEmployee(Home.java:82) ~[classes/:na]

和一长串这样的列表。

调用它的表格是：

<form name="myform" method="post" action="addEmployee" >
        <input type="submit" value="Save">
</form>

编辑：在将客户端的方法= RequestMethod.GET更改为RequestMethod.POST时，什么也没有发生，仍然出现相同的错误我在做什么错了？

Answer 1

检查完代码问题后，在客户端应用程序中，后端应用程序在8090端口上运行，而在api中，您调用的addEmployee为8080。

将此String url = "http://localhost:8080/api/addEmployee";更改为String url = "http://localhost:8090/api/addEmployee";，您应该会很好。

@RequestMapping(value = "/addEmployee", method = RequestMethod.GET)
    public String addEmployee(ModelAndView model) {



        RestTemplate restTemplate = new RestTemplate();
        String url = "http://localhost:8090/api/addEmployee";

        EmployeeInfo employee = new EmployeeInfo();
        employee.setName("Ashish");
        employee.setEmail("anyhing");
        employee.setDateOfBirth("mybirthday");
        employee.setLocation("home");

        System.out.println("WE HAVE REACHED HERE");
        String response = restTemplate.postForObject(url, employee, String.class);
        System.out.println(response);

        return "redirect:/home";
    }

Answer 2

404表示所请求的源不存在，因为以下原因之一：

没有控制器方法可以处理POST请求，因此请尝试将@RequestMapping(value = "/addEmployee", method = RequestMethod.GET)更改为@RequestMapping(value = "/addEmployee", method = RequestMethod.POST)
尝试使用此注释@RestController
我看到您正在访问此/ api / addEmployee，但我认为配置不正确？

Answer 3

我们应该使用RequestMethod.POST而不是RequestMethod.GET

@RequestMapping(value = "/addEmployee", method = RequestMethod.POST)
    public ModelAndView addEmployee(ModelAndView model) {

        RestTemplate restTemplate = new RestTemplate();
        String url = "http://localhost:8080/api/addEmployee";

        EmployeeInfo employee = new EmployeeInfo();
        employee.setName("Ashish");
        employee.setEmail("anyhing");
        employee.setDateOfBirth("mybirthday");
        employee.setLocation("home");
        ResponseEntity<String> response = restTemplate.postForEntity(url, employee, String.class);

        model.setViewName("homePage");
        return model;
    }

无法在SpringMVC中发送POST请求

3 个答案: