我想在question_response表中将一个字段定义为数字列表。
@Entity
public class QuestionResponse {
@Id
@GeneratedValue(strategy= GenerationType.AUTO)
@Column(name="question_response_id", nullable = false, updatable = false)
private Long question_response_id;
@ManyToOne(fetch = FetchType.EAGER)
@JoinColumn(name = "user_uuid")
private User users;
@ManyToOne(fetch = FetchType.EAGER)
@JoinColumn(name = "question_id")
private Question questions;
private List<Long> questionAns;
}
但是它给出了以下错误:
org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'entityManagerFactory' defined in class path resource [org/springframework/boot/autoconfigure/orm/jpa/HibernateJpaAutoConfiguration.class]: Invocation of init method failed; nested exception is javax.persistence.PersistenceException: [PersistenceUnit: default] Unable to build Hibernate SessionFactory; nested exception is org.hibernate.MappingException: Could not determine type for: java.util.Set, at table: question_response, for columns: [org.hibernate.mapping.Column(question_ans)]
我也尝试过Set,但是没有用。有人可以帮我吗?
答案 0 :(得分:0)
您可以使用:
public class Answer{
@Column(name="id_response")
private long Idresponse;
@Column(name="response")
private String response;
@JsonIgnore
@ManyToOne
@JoinColumn(name="question")
private QuestionResponse questionResponse;
}
然后在QuestionResponse类中,您可以使用如图所示的OneToMany关系,它将起作用:
@Entity
public class QuestionResponse {
@Id
@GeneratedValue(strategy= GenerationType.AUTO)
@Column(name="question_response_id", nullable = false, updatable = false)
private Long question_response_id;
@ManyToOne(fetch = FetchType.EAGER)
@JoinColumn(name = "user_uuid")
private User users;
@ManyToOne(fetch = FetchType.EAGER)
@JoinColumn(name = "question_id")
private Question questions;
@OneToMany(mappedBy = "answer", cascade = CascadeType.ALL)
private Set<Answer> answer;
}