如何跳到红宝石线

Question

我正在用ruby开发一个pwd生成器，当到达代码的某个点时，如果用户说他想重试生成pwd，则需要返回。

print "do you want to retry to generate the password? [y/n]"
    retrypwd = gets.chomp
    if retrypwd == y
    (code to jump to some lines ago)
    elsif retrypwd == n
    print "Ok, It'll be for the next time"
end

Answer 1

诀窍是使用loop并根据您的期望将其破坏或重复：

def try_again?
  loop do
    print "Would you like to try again? Y/N"
    again = gets.chomp.capitalize

    case (again)
    when 'N'
      return false
    when 'Y'
      return true
    else
      puts "Huh? I don't know what that means."
    end
  end
end

然后您可以将其合并到主程序中：

begin
  try_password
end while try_again?

您将继续尝试输入密码，直到try_again?返回false（如果您键入“ N”会发生这种情况）。