虽然命令使x值增加2而不是1

时间:2018-09-15 07:44:04

标签: php mysql

因此,我的目的是获得选中的单选按钮的值,并将其与我的数据库答案进行比较。但是,当我执行while循环时,$ x ++会从0变为2。 主页和结果页如下。预先感谢您的帮助。

Main.php

<?php
error_reporting(E_ALL ^ E_WARNING);
$con = mysqli_connect("localhost","root","","mcq");

//connection check
if (mysqli_connect_errno())
  {
  echo "Failed to connect to MySQL: " . mysqli_connect_error();
  };
  //get questions
  $questions = mysqli_query($con, "SELECT `ID`, `Question`, `Answer` FROM `main`");
  $answers = mysqli_query($con, "SELECT `ans1`, `ans2`, `ans3`, `ans4` FROM `answerlist`");
  echo("<form action='result.php' method='post'>");
  if ($questions->num_rows > 0){
    // output data of each row
    while(($row = $questions->fetch_assoc()) && ($row1 = $answers->fetch_assoc())) {

        echo ($row[ID].". ".$row[Question]."<br/>"."<input type='radio' name='id".$row[ID]."' value='".$row1[ans1]."'/>".$row1[ans1]."<br/>"."<input type='radio' name='id".$row[ID]."' value='".$row1[ans2]."'/>".$row1[ans2]."<br/>"."<input type='radio' name='id".$row[ID]."' value='".$row1[ans3]."'/>".$row1[ans3]."<br/>"."<input type='radio' name='id".$row[ID]."' value='".$row1[ans4]."'/>".$row1[ans4]);

    }
};
echo("<br/><button type='submit'>SUBMIT</button>");
echo("</form>");



?>

Result.php

<?php
$count = 0;
$con = mysqli_connect("localhost","root","","mcq");

//connection check
if (mysqli_connect_errno())
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
};

$questions = mysqli_query($con, "SELECT `ID`,`Answer` FROM `main`");

$qcount = count(mysqli_fetch_assoc($questions));
$x = 1;
while($x < $qcount){

$id = "id".$x;
$answerval = $_POST["$id"];

while($row = $questions->fetch_assoc()){
    print_r($row);
    $ans = $row['Answer'];
if($answerval == $ans){
    $count= $count + 1;
    echo("TRUE");

};

 };
     };
    echo("<br/>".$count);


?>

0 个答案:

没有答案