反序列化错误：名称空间''中的XML元素'name'已存在于当前作用域中

时间：2009-02-07 05:59:01

标签： c# xml serialization xml-serialization

这是我第一次使用XML序列化，在尝试解决此问题2天后，这让我绝对坚持。

当反序列化开始时，我收到此错误：

The XML element 'name' from namespace '' is already present in the current scope. Use XML attributes to specify another XML name or namespace for the element.

错误发生在我的代码中的这一行：

Album album = (Album)serializer.Deserialize(reader);

我不确定为什么。没有重复的“名称”节点，所以我只是没有得到它。这是从第三方REST API的HttpWebResponse接收的XML文档。

以下是完整的代码：

我的专辑类（我正在反序列化的类型）：

    public class Album
    {
        #region Constructors

        public Album() 
        { 

        }

        #endregion

        #region ElementConstants

        public static class ElementConstants
        {
            public const string aID = "aid";
            public const string Owner = "owner";
            public const string AlbumName = "name";
            public const string CoverPhotoID = "cover_pid";
            public const string CreateDate = "created";
            public const string LastModifiedDate = "modified";
            public const string Description = "description";
            public const string Location = "location";
            public const string AlbumURL = "link";
            public const string Size = "size";
            public const string Visible = "visible";
        }

        #endregion ElementConstants

        #region Public Properties

        [XmlArray(ElementName = "photos_GetAlbums_response")]
        [XmlArrayItem( "album" )]
        public Album[] Albums { get; set; }

        [XmlElement (ElementName = ElementConstants.AlbumName, DataType = "string")]
        public string AlbumID { get; set; }

        [XmlElement(ElementName = ElementConstants.aID, DataType = "int")]
        public Int32 CoverPhotoID { get; set; }

        [XmlElement(ElementName = ElementConstants.Owner, DataType = "string")]
        public string Owner { get; set; }

        [XmlElement(ElementName = ElementConstants.AlbumName, DataType = "string")]
        public string AlbumName { get; set; }

        [XmlElement(ElementName = ElementConstants.aID, DataType = "DateTime")]
        public DateTime CreateDate { get; set; }

        [XmlElement(ElementName = ElementConstants.LastModifiedDate, DataType = "DateTime")]
        public DateTime LastModifiedDate { get; set; }

        [XmlElement(ElementName = ElementConstants.Description, DataType = "string")]
        public string Description { get; set; }

        [XmlElement(ElementName = ElementConstants.Location, DataType = "string")]
        public string Location { get; set; }

        [XmlElement(ElementName = ElementConstants.AlbumURL, DataType = "string")]
        public string Link { get; set; }

        [XmlElement(ElementName = ElementConstants.Size, DataType = "size")]
        public string Size { get; set; }

        [XmlElement(ElementName = ElementConstants.Visible, DataType = "string")]
        public string Visible { get; set; }

        #endregion
    }

我的序列化程序类：

    public class Serializer
    {
        public static Album CreateAlbumFromXMLDoc(XmlDocument doc)
        {
            // Create an instance of a serializer
            var serializer = new XmlSerializer(typeof(Album));
            var reader = new StringReader(doc.ToString());

            // Deserialize the Xml Object and cast to type Album
            Album album = (Album)serializer.Deserialize(reader);

            return album;
        }
    }

我尝试反序列化的XML （在VS中调试时从Xml Doc对象复制到传递到CreateAlbumFromXMLDoc方法中）：

<?xml version="1.0" encoding="UTF-8"?>
<photos_GetAlbums_response xsi:schemaLocation="http://api.example.com/1.0/ http://api.example.com/1.0/xxx.xsd" list="true">
<album>
 <aid>3231990241086938677</aid>
 <cover_pid>7031990241087042549</cover_pid>
 <owner>1337262814</owner>
 <name>LA</name>
 <created>1233469624</created>
 <modified>1233469942</modified>
 <description>trip to LA</description>
 <location>CA</location>
 <link>http://www.example.com/album.php?aid=7333&id=1337262814</link>
 <size>48</size>
 <visible>friends</visible>
 </album>
<album>
 <aid>7031990241086936240</aid>
 <cover_pid>7031990241087005994</cover_pid>
 <owner>1337262814</owner>
 <name>Wall Photos</name>
 <created>1230437805</created>
 <modified>1233460690</modified>
 <description/>
 <location/>
 <link>http://www.example.com/album.php?aid=3296&id=1337262814</link>
 <size>34</size>
 <visible>everyone</visible>
 </album>
<album>
 <aid>7031990241086937544</aid>
 <cover_pid>7031990241087026027</cover_pid>
 <owner>1337262814</owner>
 <name>Mobile Uploads</name>
 <created>1231984989</created>
 <modified>1233460349</modified>
 <description/>
 <location/>
 <link>http://www.example.com/album.php?aid=6300&id=1337262814</link>
 <size>3</size>
 <visible>friends</visible>
 </album>
<album>
 <aid>7031990241086936188</aid>
 <cover_pid>7031990241087005114</cover_pid>
 <owner>1337262814</owner>
 <name>Christmas 2008</name>
 <created>1230361978</created>
 <modified>1230362306</modified>
 <description>My Album</description>
 <location/>
 <link>http://www.example.com/album.php?aid=5234&id=1337262814</link>
 <size>50</size>
 <visible>friends</visible>
 </album>
<album>
 <aid>7031990241086935881</aid>
 <cover_pid>7031990241087001093</cover_pid>
 <owner>1637262814</owner>
 <name>Hock</name>
 <created>1229889219</created>
 <modified>1229889235</modified>
 <description>Misc Pics</description>
 <location/>
 <link>http://www.example.com/album.php?aid=4937&id=1637262814</link>
 <size>1</size>
 <visible>friends-of-friends</visible>
 </album>
<album>
 <aid>7031990241086935541</aid>
 <cover_pid>7031990241086996817</cover_pid>
 <owner>1637262814</owner>
 <name>Test Album 2 (for work)</name>
 <created>1229460455</created>
 <modified>1229460475</modified>
 <description>this is a test album</description>
 <location/>
 <link>http://www.example.com/album.php?aid=4547&id=1637262814</link>
 <size>1</size>
 <visible>everyone</visible>
 </album>
<album>
 <aid>7031990241086935537</aid>
 <cover_pid>7031990241086996795</cover_pid>
 <owner>1637262814</owner>
 <name>Test Album (for work)</name>
 <created>1229459168</created>
 <modified>1229459185</modified>
 <description>Testing for work</description>
 <location/>
 <link>http://www.example.com/album.php?aid=4493&id=1637262814</link>
 <size>1</size>
 <visible>friends</visible>
 </album>
 </photos_GetAlbums_response>

旁注：为了它的原因，我将该XML粘贴到XML Notepad 2007中，它告诉我：

您的XML文档不包含xml-stylesheet处理指令。要提供XSLT转换，请将以下内容添加到文件顶部并相应地编辑href属性：

我认为这并不意味着它的格式不正确或只是需要注意的事情。

所以..

我的最终目标是明显地传递这个该死的错误，并且一旦我能够通过错误，就可以使用上面的代码获取一系列专辑。我还想确保我的代码在使用我的Album类中的Album []属性或我可能在这里丢失的任何其他内容时，尝试检索专辑的背面是正确的。我认为它非常接近，应该可以工作，但事实并非如此。

后续。从那以后，我一直在拔头发。

这是最新的。我现在没有使用过某些东西（来自Marc），比如Enum等。我可能会稍后改变它。我也拿出了日期时间的东西，因为它看起来很奇怪而且我没有得到错误，没有...至少还没有。现在的主要问题仍然是我该死的XML。

我猜这个格式似乎仍然存在问题？除非它掩盖了另一个问题，否则没有任何线索。这让我疯狂。

我现在在反序列化开始时出现此错误：

Data at the root level is invalid. Line 1, position 1.

我的代码中此行发生错误：GetAlbumsResponse album =（GetAlbumsResponse）serializer.Deserialize（reader）;

我如何将响应纳入XmL文档：

public static XmlDocument GetResponseXmlDocument(HttpWebResponse response)
        {
            Stream dataStream = null; // stream from WebResponse
            XmlDocument doc = new XmlDocument();

            if (doc == null)
            {
                throw new NullReferenceException("The web reponse was null");
            }

            // Get the response stream so we can read the body of the response
            dataStream = response.GetResponseStream();

            // Open the stream using a StreamReader for easy access
            StreamReader reader = new StreamReader(dataStream);

            // Load response into string variable so that we can then load into an XML doc
            string responseString = reader.ReadToEnd();

            // Create an XML document & load it with the response data
            doc.LoadXml(responseString);

            // Final XML document that represents the response
            return doc;
        }

我的相册类＆amp;根级别等级（感谢Marc的帮助......我现在得到它）：

namespace xxx.Entities
{

    [Serializable, XmlRoot("photos_GetAlbums_response")]
    public class GetAlbumsResponse
    {
        [XmlElement("album")]
        public List<Album> Albums { get; set; }

        [XmlAttribute("list")]
        public bool IsList { get; set; }
    }

    public class Album
    {
        #region Constructors

        public Album()
        {

        }

        #endregion

        #region ElementConstants

        /// <summary>
        /// Constants Class to eliminate use of Magic Strings (hard coded strings)
        /// </summary>
        public static class ElementConstants
        {
            public const string aID = "aid";
            public const string Owner = "owner";
            public const string AlbumName = "name";
            public const string CoverPhotoID = "cover_pid";
            public const string CreateDate = "created";
            public const string LastModifiedDate = "modified";
            public const string Description = "description";
            public const string Location = "location";
            public const string AlbumURL = "link";
            public const string Size = "size";
            public const string Visible = "visible";
        }

        #endregion ElementConstants

        #region Public Properties

        [XmlElement (ElementName = ElementConstants.aID, DataType = "string")]
        public string AlbumID { get; set; }

        [XmlElement(ElementName = ElementConstants.CoverPhotoID, DataType = "int")]
        public Int32 CoverPhotoID { get; set; }

        [XmlElement(ElementName = ElementConstants.Owner, DataType = "string")]
        public string Owner { get; set; }

        [XmlElement(ElementName = ElementConstants.AlbumName, DataType = "string")]
        public string AlbumName { get; set; }

        public string Created { get; set; }

        public DateTime Modified { get; set; }

        [XmlElement(ElementName = ElementConstants.Description, DataType = "string")]
        public string Description { get; set; }

        [XmlElement(ElementName = ElementConstants.Location, DataType = "string")]
        public string Location { get; set; }

        [XmlElement(ElementName = ElementConstants.AlbumURL, DataType = "string")]
        public string Link { get; set; }

        public string Size { get; set; }

        [XmlElement(ElementName = ElementConstants.Visible, DataType = "string")]
        public string Visible { get; set; }

        #endregion
    }
}

我的序列化程序类：

namespace xxx.Utilities
{
    public class Serializer
    {
        public static List<Album> CreateAlbumFromXMLDoc(XmlDocument doc)
        {
            // Create an instance of a serializer
            var serializer = new XmlSerializer(typeof(Album));
            var reader = new StringReader(doc.ToString());

            // Deserialize the Xml Object and cast to type Album
            GetAlbumsResponse album = (GetAlbumsResponse)serializer.Deserialize(reader);

            return album.Albums;
        }
    }
}

真正的XML传入，我试图反序列化（是的，它确实有xmlns）：

<?xml version="1.0" encoding="UTF-8"?>
<photos_GetAlbums_response xmlns="http://api.example.com/1.0/" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://api.example.com/1.0/ http://api.example.com/1.0/xxx.xsd" list="true">
  <album>
    <aid>7321990241086938677</aid>
    <cover_pid>7031990241087042549</cover_pid>
    <owner>1124262814</owner>
    <name>Album Test 1</name>
    <created>1233469624</created>
    <modified>1233469942</modified>
    <description>Our trip</description>
    <location>CA</location>
    <link>http://www.example.com/album.php?aid=7733&id=1124262814</link>
    <size>48</size>
    <visible>friends</visible>
  </album>
  <album>
    <aid>231990241086936240</aid>
    <cover_pid>7042330241087005994</cover_pid>
    <owner>1124262814</owner>
    <name>Album Test 2</name>
    <created>1230437805</created>
    <modified>1233460690</modified>
    <description />
    <location />
    <link>http://www.example.com/album.php?aid=5296&id=1124262814</link>
    <size>34</size>
    <visible>everyone</visible>
  </album>
  <album>
    <aid>70319423341086937544</aid>
    <cover_pid>7032390241087026027</cover_pid>
    <owner>1124262814</owner>
    <name>Album Test 3</name>
    <created>1231984989</created>
    <modified>1233460349</modified>
    <description />
    <location />
    <link>http://www.example.com/album.php?aid=6600&id=1124262814</link>
    <size>3</size>
    <visible>friends</visible>
  </album>
</photos_GetAlbums_response>

9 个答案:

答案 0 :(得分：5)

就个人而言，我不会在这里使用常量 - 它们很难发现错误（因为你可能没有重复使用它们，所以不要添加太多）。例如：

    [XmlElement (ElementName = ElementConstants.AlbumName, DataType = "string")]
    public string AlbumID { get; set; }
...
    [XmlElement(ElementName = ElementConstants.AlbumName, DataType = "string")]
    public string AlbumName { get; set; }

看起来对我怀疑......

更简单的方法是将您想要的xml写入文件（例如foo.xml）并使用：

xsd foo.xml
xsd foo.xsd /classes

然后查看foo.cs。

答案 1 :(得分：3)

我们开始......注意xml无效（&应为&amp;;使用未声明的xsi命名空间别名）。另请注意，我为可见性添加了枚举，添加了将long转换为DateTime的处理，并添加了包装类型：

using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.IO;
using System.Xml;
using System.Xml.Serialization;

static class Program
{
    const string xml = @"<?xml version=""1.0"" encoding=""UTF-8""?>
<photos_GetAlbums_response
    xmlns:xsi=""http://www.w3.org/2001/XMLSchema-instance""
    xsi:schemaLocation=""http://api.example.com/1.0/ http://api.example.com/1.0/xxx.xsd""
    list=""true"">
<album>
 <aid>3231990241086938677</aid>
 <cover_pid>7031990241087042549</cover_pid>
 <owner>1337262814</owner>
 <name>LA</name>
 <created>1233469624</created>
 <modified>1233469942</modified>
 <description>trip to LA</description>
 <location>CA</location>
 <link>http://www.example.com/album.php?aid=7333&amp;id=1337262814</link>
 <size>48</size>
 <visible>friends</visible>
 </album>
<album>
 <aid>7031990241086936240</aid>
 <cover_pid>7031990241087005994</cover_pid>
 <owner>1337262814</owner>
 <name>Wall Photos</name>
 <created>1230437805</created>
 <modified>1233460690</modified>
 <description/>
 <location/>
 <link>http://www.example.com/album.php?aid=3296&amp;id=1337262814</link>
 <size>34</size>
 <visible>everyone</visible>
 </album>
<album>
 <aid>7031990241086937544</aid>
 <cover_pid>7031990241087026027</cover_pid>
 <owner>1337262814</owner>
 <name>Mobile Uploads</name>
 <created>1231984989</created>
 <modified>1233460349</modified>
 <description/>
 <location/>
 <link>http://www.example.com/album.php?aid=6300&amp;id=1337262814</link>
 <size>3</size>
 <visible>friends</visible>
 </album>
<album>
 <aid>7031990241086936188</aid>
 <cover_pid>7031990241087005114</cover_pid>
 <owner>1337262814</owner>
 <name>Christmas 2008</name>
 <created>1230361978</created>
 <modified>1230362306</modified>
 <description>My Album</description>
 <location/>
 <link>http://www.example.com/album.php?aid=5234&amp;id=1337262814</link>
 <size>50</size>
 <visible>friends</visible>
 </album>
<album>
 <aid>7031990241086935881</aid>
 <cover_pid>7031990241087001093</cover_pid>
 <owner>1637262814</owner>
 <name>Hock</name>
 <created>1229889219</created>
 <modified>1229889235</modified>
 <description>Misc Pics</description>
 <location/>
 <link>http://www.example.com/album.php?aid=4937&amp;id=1637262814</link>
 <size>1</size>
 <visible>friends-of-friends</visible>
 </album>
<album>
 <aid>7031990241086935541</aid>
 <cover_pid>7031990241086996817</cover_pid>
 <owner>1637262814</owner>
 <name>Test Album 2 (for work)</name>
 <created>1229460455</created>
 <modified>1229460475</modified>
 <description>this is a test album</description>
 <location/>
 <link>http://www.example.com/album.php?aid=4547&amp;id=1637262814</link>
 <size>1</size>
 <visible>everyone</visible>
 </album>
<album>
 <aid>7031990241086935537</aid>
 <cover_pid>7031990241086996795</cover_pid>
 <owner>1637262814</owner>
 <name>Test Album (for work)</name>
 <created>1229459168</created>
 <modified>1229459185</modified>
 <description>Testing for work</description>
 <location/>
 <link>http://www.example.com/album.php?aid=4493&amp;id=1637262814</link>
 <size>1</size>
 <visible>friends</visible>
 </album>
 </photos_GetAlbums_response>";
    static void Main()
    {
        XmlSerializer ser = new XmlSerializer(typeof(GetAlbumsResponse));
        GetAlbumsResponse response;
        using (StringReader reader = new StringReader(xml))
        {
            response = (GetAlbumsResponse)ser.Deserialize(reader);
        }

    }
}

[Serializable, XmlRoot("photos_GetAlbums_response")]
public class GetAlbumsResponse
{
    [XmlElement("album")]
    public List<Album> Albums {get;set;}

    [XmlAttribute("list")]
    public bool IsList { get; set; }
}
public enum AlbumVisibility
{
    [XmlEnum("")]
    None,
    [XmlEnum("friends")]
    Friends,
    [XmlEnum("friends-of-friends")]
    FriendsOfFriends,
    [XmlEnum("everyone")]
    Everyone

}
[Serializable]
public class Album
{
    static readonly DateTime epoch = new DateTime(1970, 1, 1);
    static long SerializeDateTime(DateTime value)
    {
        return (long)((value - epoch).TotalSeconds);
    }
    static DateTime DeserializeDateTime(long value)
    {
        return epoch.AddSeconds(value);
    }
    [XmlElement("aid")]
    public long AlbumID { get; set; }

    [XmlElement("cover_pid")]
    public long CoverPhotoID { get; set; }

    [XmlElement("owner")]
    public long Owner { get; set; }

    [XmlElement("name")]
    public string AlbumName { get; set; }

    [XmlIgnore]
    public DateTime CreateDate { get; set; }

    [XmlElement("created"), Browsable(false)]
    [EditorBrowsable(EditorBrowsableState.Never)]
    public long CreateDateInt64 {
        get {return SerializeDateTime(CreateDate);}
        set {CreateDate = DeserializeDateTime(value);}
    }

    [XmlIgnore]
    public DateTime LastModifiedDate { get; set; }

    [XmlElement("modified"), Browsable(false)]
    [EditorBrowsable(EditorBrowsableState.Never)]
    public long LastModifiedDateInt64
    {
        get { return SerializeDateTime(LastModifiedDate); }
        set { LastModifiedDate = DeserializeDateTime(value); }
    }

    [XmlElement("description")]
    public string Description { get; set; }

    [XmlElement("location")]
    public string Location { get; set; }

    [XmlElement("link")]
    public string Link { get; set; }

    [XmlElement("size")]
    public int Size { get; set; }

    [XmlElement("visible")]
    public AlbumVisibility Visibility { get; set; }
}

答案 2 :(得分：2)

（2月8日）首先，将xml视为字符串（用于读取）不会导致错误。

问题是命名空间（xmlns 没有 xsi）;这不是早期的xml，所以我不能包含它...基本上，你需要告诉序列化器它：

[Serializable, XmlRoot("photos_GetAlbums_response",
    Namespace="http://api.example.com/1.0/")]
public class GetAlbumsResponse { /* code as before */ }

[Serializable, XmlType(Namespace="http://api.example.com/1.0/")]
public class Album { /* code as before */ }

在这种情况下，名称空间的常量将有意义（因为您正在重新使用它）。

如果您显示的xml是准确的，那么链接仍然是损坏的，但是......但也许这只是复制/粘贴（即在您知道错误之前不要应用此更改...）：您需要 &amp;（不是&）。在最粗糙的层面上建议一些“替换”...... 

string fixedXml = xml.Replace("&", "&amp;");

（虽然更精确的东西可能更好 - 也许是正则表达式）

请注意，对于不同的数据，我还必须制作一些数据字符串（而不是长）：

[XmlElement("aid")]
public string AlbumID { get; set; }

[XmlElement("cover_pid")]
public string CoverPhotoID { get; set; }

[XmlElement("owner")]
public string Owner { get; set; }

通过这些更改（主要是我的原始代码），它可以正常工作。

当然，到此为止你应该考虑“我希望我used xsd”。

答案 3 :(得分：1)

那么，

来自Microsoft的link针对您的问题

答案 4 :(得分：1)

是的 - 相册绝对不是XML中的根节点。

我建议你做的是创建一个包含相册列表的GetAlbumsResponse类，并将反序列化代码移动到包装类。

基本上，从Album类定义中删除根元素，然后：

  [XmlRoot (ElementName="GetAlbums_response")]
public class GetAlbumsResponse
{
    #region Constructors

    public GetAlbumsResponse()
    {

    }

    #endregion



    [XmlArray(ElementName="album")]
    public List<Album> Albums{get;set;}

    ... deserialization code...

}

答案 5 :(得分：1)

好的 - 我编写了一个例子。我看了一下Facebook API，现在这是一个完整的工作示例。  试试这个：

[XmlRoot("photos_getAlbums_response", Namespace="http://api.facebook.com/1.0/")]
public class GetAlbumsResponse
{
    public GetAlbumsResponse() 
    {    
    }

    [XmlElement("album")]
    public List<Album> Albums { get; set; }
}

public class Album
{
    [XmlElement("aid")]
    public long Aid{get;set;}

    [XmlElement("cover_pid")]
    public long CoverPid{get;set;}

    [XmlElement("owner")]
    public long Owner{get;set;}

    [XmlElement("name")]
    public string Name{get;set;}

    [XmlElement("created")]
    public long Created{get;set;}

    [XmlElement("modified")]
    public long Modified{get;set;}

    [XmlElement("description")]
    public string Description{get;set;}

    [XmlElement("location")]
    public string Location{get;set;}

    [XmlElement("link")]
    public string Link{get;set;}

    [XmlElement("size")]
    public int Size{get;set;}

    [XmlElement("visible")]
    public string Visible{get;set;}

    public Album()
    {}
}

class XmlUtils
{
    public static T DeserializeFromXml<T>(string xml)
    {
        T result;
        XmlSerializer ser = new XmlSerializer(typeof(T));
        using (TextReader tr = new StringReader(xml))
        {
            result = (T)ser.Deserialize(tr);
        }
        return result;
    }
}

现在..来自Facebook API的xml photos_getAlbums_response，

您可以像这样反序列化：

 GetAlbumsResponse response = XmlUtils.DeserializeFromXml<GetAlbumsResponse>(xmlResponseString);

答案 6 :(得分：1)

适用于当前代码的Xml是这样的：

<Album><photos_GetAlbums_response>
<Album>
   <photos_GetAlbums_response>
      <Album>
         <photos_GetAlbums_response> ....

一个响应，其中包含一系列专辑，其中每个专辑都有一个响应，即一个专辑数组......等等。

无论如何，我已经在你的另一个问题上帮助了你，甚至还没有创建一个完整的代码示例。你为什么要为同样的问题创建另一个问题？

答案 7 :(得分：1)

Use System.Xml.XmlDocument to parse the input.编写代码以自行提取数据不应超过一个小时。

答案 8 :(得分：0)

这是一个非常古老的线程，但我在尝试在相同的XmlArray名称下在同一个类中序列化两个不同的列表类型时遇到了同样的问题，例如

    <Root>
       <ArrayNode>
         <SubnodeType1>...</SubnodeType1>
         <SubnodeType1>...</SubnodeType1>
       </ArrayNode>
    </Root>
Or
    <Root>
       <ArrayNode>
         <SubnodeType2>...</SubnodeType2>
         <SubnodeType2>...</SubnodeType2>
       </ArrayNode>
    </Root>

对我有用的是使用类似装饰：

[XmlRoot(Namespace = "", ElementName = "Root")]
public class Root
{
    [XmlArray(ElementName = "ArrayNode", Namespace = "", IsNullable = false, Order = 1)]
    [XmlArrayItem("SubnodeType1")]
    public List<SubnodeType1> SubnodeType1 { get; set; }
    [XmlArray(ElementName = "ArrayNode", Namespace = "", IsNullable = false, Order = 2)]
    [XmlArrayItem("SubnodeType2")]
    public List<SubnodeType2> SubnodeType2 { get; set; }
}

希望能帮助别人：）

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