Question

在下面的代码中，可以有多个FigureA.objects;这些由输出中的小写字母表示。每个对象都有其键/值（即shape：circle）的名称和特征字典。

    for objectsA in figureA.objects:
        thisObjectA = figureA.objects[objectsA]
        #print the objects lower-case letter (the shape's identifier)
        print objectsA

        for attributesA in thisObjectA.attributes:
            #print the attribute's for the object name:characteristic
            print attributesA, thisObjectA.attributes[attributesA]

输出为：

a
shape circle
fill no
size very large
b
shape plus
fill yes
angle 0
inside a
size small

如何代替打印，如何创建新的字符串列表或仅值的新列表？当然，不包括小写的a和b。保持顺序（a的属性，然后是b的属性，等等）也很重要

非常感谢您的帮助！

Answer 1

在您的评论中，您需要以下内容：

 myList = []
 for objectsA in figureA.objects:
        thisObjectA = figureA.objects[objectsA]
        #print the objects lower-case letter (the shape's identifier)
        print objectsA

        for attributesA in thisObjectA.attributes:
            #print the attribute's for the object name:characteristic
            print attributesA, thisObjectA.attributes[attributesA]
            myList.append(attributesA + " " + thisObjectA.attributes[attributesA])

  myList.sort()

这应该创建所有属性的列表并对其进行排序

从多个词典创建新列表

1 个答案: