Question

我不断收到此错误：我正在为类创建的Mad Lib中的线程“ main” java.util.InputMismatchException中的异常。我不是在问如何使代码更好，而是为什么它不会起作用。我只会在第三个形容词之后收到此通知。这是我的代码：

import java.util.Scanner;

public class scanner_practice {
public static void main(String[] args) {
// Housekeeping
Scanner kb = new Scanner(System.in);
String word, story;
int intVar;
double dubVar;

// Introduction
System.out.println("Hi there! I have a great story to tell, but I don't remember some of the words.");
System.out.println("Will you help me? Hooray! Thank you! Here we go...");

// Instructions
System.out.println("\nWhen I ask you for a word or number, just type it. I'll handle the rest.");

// Collect values and bulid the story
System.out.print("Verb: ");
word = kb.next();

story = "I am Dr. Pink and I am destined to " + word;

System.out.print("Adjective: ");
word = kb.next();
kb.nextLine(); // Stops the program skipping
story += "the world! Unfortunately the \n" + "world is full of " + word;

System.out.print("Plural noun:  ");
word = kb.nextLine();

story += " " + word;


System.out.print("Adjective: ");
word = kb.next();

story += "that do not agree. So this is \n" + "my " + word;

System.out.print("Adjective: ");
intVar = kb.nextInt();

story += " plan: To start with, I'll need to build my " + intVar;

System.out.print("Adjetive ");
word = kb.next();

story += " hideout in an /n" + "abandoned " + word; 

System.out.print("Company Name: ");
word = kb.next();

story += " complex in the middle of the" + word; 

System.out.print("Type of Place: ");
word = kb.next();
story += ". All \n" + "the " + word; 

System.out.print("Adjective: ");
word = kb.next();
story += "will address me as 'The Great and " + word; 

System.out.print("Occupation (plural): ");
word = kb.next();
kb.nextLine(); // Stops the program skipping
story += " Dr. Pink.' I will \n" + "hire some  " + word; 

System.out.print("Plural event): ");
word = kb.nextLine();
story += "to design a machine to trigger \n" + "a huge  " + word; 
System.out.print("Plural noun: ");
word = kb.next();
story += " whenever I want it to. And if they don't want to build it, I \n" + "will capture their " + word; 

System.out.print("Something you hate doing: ");
word = kb.next();
story += " and threaten to make them " + word + "for hours on end. \n" + "Muwahahahahaha!"; 


// Print out the story
System.out.println(story);
}

}

我需要解决什么？这是今晚的事情……所以，如果我能迅速得到答案，那对我来说意味着世界！谢谢你！

Answer 1

学习如何进行错误排查与学习如何编码:-)

几乎一样重要

A。首先查看the docs for InputMismatchException，以获取发生时间和原因的线索：

由扫描程序抛出以表明检索到的令牌没有匹配预期类型的模式，或者令牌超出了预期类型的范围。

B。查看完整的堆栈跟踪。跟踪提供有关错误的上下文，例如发生错误的行以及正在调用的方法：

... at java.util.Scanner。 nextInt （Scanner.java:2076）
在scan_practice.main（scanner_practice.java： 41 ）

C。查看错误行附近的Java代码：

    line 40: System.out.print("Adjective: ");

结论：“形容词”可能不是整数。

使用jGRASP时，线程“ main”中的异常java.util.InputMismatchException

1 个答案: