Question

我尝试模拟（使用Rhyno mock）同步服务的行为。

这是一个例子：我得到了一个名为void GetServerState（）的方法的服务。由于此方法是同步的，因此它是无效的，但是当它被调用时，它将调用代理并调用事件GetServerStateCompleted（object，eventargs）。在这一点上，我希望每个人都跟着我; - ）

现在，让我们看一下mock（它实际上是一个存根，但没关系）

public class MyStub
{
 protected MockRepository MockRepository {get;set;}
 public IMyService MyService {get;set;} //the service with GetServerState() Method
 protected delegate void DelegateVoid(); //for easy writting

 public MyStub()
 {
   MockRepository = new MockRepository ();
   MyService = MockRepository.Stub<IMyService >();

   //And now, let's try to mock the behaviour
   MyService.Stub(sm => sm.GetServerState())
                .IgnoreArguments()
                .Do((DelegateVoid)GetServerStateCompletedBehaviour);
 }

 //the method that should be launched when someone call GetServerState on the Stub
 protected void GetServerStateCompletedBehaviour()
 {
  MyService.Raise(x=>x.GetServerStateCompleted+=null,MyService,new EventArgs());
 }
}

//And here is how I would like to use it
[TestMethod]
void Test()
{
 try
 {
  IMyService Stub = new MyStub().MyService;
  Stub += new EventHandler(EventMethod);
  Stub.GetServerState();
  Assert.Fail();
 }
 catch(MyException){}
}

void EventMethod(Object sender, EventArgs e)
{
 Throw new MyException();
}

因为一切似乎都适合我，这段代码根本不起作用。是否有人开始解释为什么它不起作用？

THX，

Answer 1

我发现了什么问题：

public MyStub()
 {
   MockRepository = new MockRepository ();
   //MyService = MockRepository.Stub<IMyService >(); //Stupid Stupid Stupid !!!
   MyService = MockRepository.GenerateStub<IMyService >();

   //And now, let's try to mock the behaviour
   MyService.Stub(sm => sm.GetServerState())
                .IgnoreArguments()
                .Do((DelegateVoid)GetServerStateCompletedBehaviour);
 }

无法使用Rhino mock模拟异步服务行为

1 个答案: