Question

在打印代码时，它可以运行，但似乎没有运行coinflip()函数。目前仅尝试打印出第一个马串，然后随机向前移动。

#include <iostream>
#include <string>
#include <time.h>
#include <stdlib.h>
using namespace std;

string h0 = "0................";
string h1 = "1................";
string h2 = "2................";
string h3 = "3................";
string h4 = "4................";
int position0 = 0;
string coinflip0(string h0);

int main(){

   cout << "Press Enter to begin! " <<endl;
   cin.ignore();
   std::cout << h0 << endl; //print string
   cout << h1 << endl;
   cout << h2 << endl;
   cout << h3 << endl;
   cout << h4 << endl;

//      srand(time(NULL));//time goes back to zero for each loop

   while(h0.at(16) != 0) {
        cout << "\n Press Enter to continue " << endl;
        cin.ignore();

        string coinflip0(h0); // call function
        cout << h0 << endl; //print new string
   } //end while
} // end main

string coinflip0(string h0) {

   // find random number(0 or 1)
   int num = rand() % 2;
        cout << num << endl;
   position0 = position0 + num;

   if(num==1){
        std::swap(h0[position0], h0[position0+1]);
   } // end if

   return h0;
}//end coin flip

输出：

Press Enter to begin!

0................
1................
2................
3................
4................

 Press Enter to continue

0................

 Press Enter to continue

0................

 Press Enter to continue

0................

 Press Enter to continue

Answer 1

string coinflip0(h0); // call function

这实际上不是函数调用。这是一个变量声明，类似于：

string coinflip0 = h0;

要调用该函数，请省略string。一个简单的coinflip0(h0)就可以解决问题。我认为您想将结果分配回h0，所以也可以这样做：

h0 = coinflip0(h0);

赛马程序，忽略了函数调用

1 个答案: