Question

在这里呆了几个小时。我正在尝试从Windows计算机上获取软件列表，并使用$ env：userprofile位置和文件“ Software Inventories \ $ Username.csv”的路径将该列表作为CSV导出为

我收到以下错误

Export-Csv : Could not find a part of the path 'C:\Users\mylogin\Software Inventories\@{UserName=domain\mylogin}.csv'.
At C:\Users\mylogin\Dropbox\Powershell\GetSoftwareList.ps1:24 char:191
+ ... e, Vendor, Version | Sort-Object DisplayName | Export-Csv -Path $Path
+                                                    ~~~~~~~~~~~~~~~~~~~~~~
    + CategoryInfo          : OpenError: (:) [Export-Csv], DirectoryNotFoundException
    + FullyQualifiedErrorId : FileOpenFailure,Microsoft.PowerShell.Commands.ExportCsvCommand

代码如下：

$ComputerName = Read-Host 'Enter IP or computer name'
$WindowsVersion = Get-WmiObject -ComputerName $ComputerName -Credential 'domain\myadmin' -Class Win32_OperatingSystem | ForEach-Object -MemberName Caption


If ($WindowsVersion -match 'Microsoft Windows 10 Enterprise'){

    $Username = Get-CimInstance -ComputerName $ComputerName -ClassName Win32_ComputerSystem | Select-Object UserName
    $Path = Join-Path $env:userprofile "Software Inventories\$Username.csv"
    Get-CimInstance -ComputerName $ComputerName -Credential "domain\myadmin" -ClassName Win32_InstalledWin32Program | Select Name, Vendor, Version | Sort-Object Name | Export-Csv -Path $Path
    Write-Host "Windows version is $WindowsVersion"

}Elseif ($WindowsVersion -match 'Microsoft Windows 7 Enterprise') {

    $Username = Get-WmiObject -ComputerName $ComputerName -Class Win32_ComputerSystem | Select-Object UserName
    $Path = Join-Path $env:userprofile "Software Inventories\$Username.csv"
    Get-WmiObject -ComputerName $ComputerName -Credential 'domain\myadmin' -Class Win32Reg_AddRemovePrograms | Select DisplayName, Vendor, Version | Sort-Object DisplayName | Export-Csv -Path $Path
    Write-Host "Windows version is $WindowsVersion"

我没有正确使用Join-Path吗？

另一方面，如何从$ Username中仅获取用户名作为字符串，而忽略其余部分？

Answer 1

变量$ UserName是一个哈希表，具有一个名为UserName的属性和一个domain \ mylogin的值。要仅选择属性的值，请使用Select-Object中的ExpandProperty参数。

$Username = Get-CimInstance -ComputerName $ComputerName -ClassName Win32_ComputerSystem | Select-Object -ExpandProperty UserName

Answer 2

$Username = (Get-CimInstance -ComputerName $ComputerName -ClassName Win32_ComputerSystem | Select-Object -ExpandProperty UserName).Split('\')[1]
$Username = (Get-WmiObject -ComputerName $ComputerName -Class Win32_ComputerSystem | Select-Object -ExpandProperty UserName).Split('\')[1]

Powershell找不到路径的一部分

2 个答案: