public class ConsolidatedChild
{
public string School { get; set; }
public string Friend { get; set; }
public string FavoriteColor { get; set; }
public List<Child> Children { get; set; }
}
public class Child
{
public string School { get; set; }
public string Name { get; set; }
public string Address { get; set; }
public string Friend { get; set; }
public string Mother { get; set; }
public string FavoriteColor { get; set; }
}
鉴于上面的两个类,我想使用LINQ从List创建一个List,按School,Friend和FavoriteColor属性分组。 LINQ可以实现吗?
请忽略这些属性,代码的编写只是为了帮助解决问题。
答案 0 :(得分:393)
易:
var consolidatedChildren =
from c in children
group c by new
{
c.School,
c.Friend,
c.FavoriteColor,
} into gcs
select new ConsolidatedChild()
{
School = gcs.Key.School,
Friend = gcs.Key.Friend,
FavoriteColor = gcs.Key.FavoriteColor,
Children = gcs.ToList(),
};
var consolidatedChildren =
children
.GroupBy(c => new
{
c.School,
c.Friend,
c.FavoriteColor,
})
.Select(gcs => new ConsolidatedChild()
{
School = gcs.Key.School,
Friend = gcs.Key.Friend,
FavoriteColor = gcs.Key.FavoriteColor,
Children = gcs.ToList(),
});
答案 1 :(得分:198)
给出一个清单:
var list = new List<Child>()
{
new Child()
{School = "School1", FavoriteColor = "blue", Friend = "Bob", Name = "John"},
new Child()
{School = "School2", FavoriteColor = "blue", Friend = "Bob", Name = "Pete"},
new Child()
{School = "School1", FavoriteColor = "blue", Friend = "Bob", Name = "Fred"},
new Child()
{School = "School2", FavoriteColor = "blue", Friend = "Fred", Name = "Bob"},
};
查询看起来像:
var newList = list.GroupBy(x => new {x.School, x.Friend, x.FavoriteColor})
.Select(y => new ConsolidatedChild()
{
FavoriteColor = y.Key.FavoriteColor,
Friend = y.Key.Friend,
School = y.Key.School,
Children = y.ToList()
}
);
测试代码:
foreach(var item in newList)
{
Console.WriteLine("School: {0} FavouriteColor: {1} Friend: {2}", item.School,item.FavoriteColor,item.Friend);
foreach(var child in item.Children)
{
Console.WriteLine("\t Name: {0}", child.Name);
}
}
结果:
School: School1 FavouriteColor: blue Friend: Bob
Name: John
Name: Fred
School: School2 FavouriteColor: blue Friend: Bob
Name: Pete
School: School2 FavouriteColor: blue Friend: Fred
Name: Bob