我有两个要链接调用的类(主->执行->计算)。但是,问题是当我使用时:
&calculate::addition;
即使编译器未返回任何错误,也不会调用Addition。如果我尝试删除对
的引用calculate::addition;
编译器返回错误
error: invalid use of non-static member function ‘void calculate::addition(double&, double, double)’
case 'a' : *calculate::addition; break;
^~~~~~~~
在void之前使用static尝试过,结果与引用相同。
#include <iostream>
class execute{
public:
void exec(char);
}jalan;
class calculate {
public:
void addition(double&, double, double);
void substraction(double&, double, double);
void multiply(double&, double, double);
void division(double&, double, double);
};
int main(void){
static double a, b;
static double result;
std::cout << "Type a, b, c, or d" << std::endl;
std::cout << "a. Addition\nb. Substraction\nc. Multiply\nd. Division" << std::endl;
std::cout << "Your Input: ";
static char option;
option = getchar();
std::cout << "First value: ";
std::cin >> a;
std::cout << "Next value: ";
std::cin >> b;
jalan.exec(option);
std::cout << result << std::endl;
return 0;
}
void execute::exec (char option){
switch(option){
case 'a' : &calculate::addition; break;
case 'b' : &calculate::substraction; break;
case 'c' : &calculate::multiply; break;
case 'd' : &calculate::division; break;
}
}
void calculate::addition(double& result, double a, double b){
result = a+b;
}
void calculate::substraction(double& result, double a, double b){
result = a-b;
}
void calculate::multiply(double& result, double a, double b){
result = a*b;
}
void calculate::division(double& result, double a, double b){
result = a/b;
}
答案 0 :(得分:0)
您的代码中有几个问题。让我们开始吧:
error: invalid use of non-static member function ‘void calculate::addition(double&, double, double)’ case 'a' : *calculate::addition; break;
这意味着您必须创建一个calcute实例或使用static void addition(double&, double, double);
之类的静态标记方法
因此将您的班级更改为
class calculate {
public:
static void addition(double&, double, double);
static void substraction(double&, double, double);
static void multiply(double&, double, double);
static void division(double&, double, double);
};
下一个问题是,在switch语句中,您仅创建指向函数的指针
void execute::exec (char option){
switch(option){
case 'a' : &calculate::addition; break;
case 'b' : &calculate::substraction; break;
case 'c' : &calculate::multiply; break;
case 'd' : &calculate::division; break;
}
}
这从不执行任何功能,而只是创建一个立即被丢弃的功能指针。
为了使您的代码正常工作,请考虑以下代码(请注意代码中的注释,这些注释解释了所需的更改):
#include <iostream>
class execute
{
public:
void exec(char, double&, double, double);
}jalan;
class calculate {
public: // added static keyword so you do not need to create a class instance
static void addition(double&, double, double);
static void substraction(double&, double, double);
static void multiply(double&, double, double);
static void division(double&, double, double);
};
int main(void){
static double a, b;
static double result;
std::cout << "Type a, b, c, or d" << std::endl;
std::cout << "a. Addition\nb. Subtraction\nc. Multiply\nd. Division" << std::endl;
std::cout << "Your Input: ";
static char option;
option = getchar();
std::cout << "First value: ";
std::cin >> a;
std::cout << "Next value: ";
std::cin >> b;
jalan.exec(option, result, a, b); // you need to pass the arguments which you want to use and modify
std::cout << result << std::endl;
return 0;
}
void execute::exec (char option, double& res, double a, double b){
switch(option){ // changed the function pointers to actual calls to the functions
case 'a' : calculate::addition(res, a, b); break;
case 'b' : calculate::substraction(res, a, b); break;
case 'c' : calculate::multiply(res, a, b); break;
case 'd' : calculate::division(res, a, b); break;
}
}
void calculate::addition(double& result, double a, double b){
result = a+b;
}
void calculate::substraction(double& result, double a, double b){
result = a-b;
}
void calculate::multiply(double& result, double a, double b){
result = a*b;
}
void calculate::division(double& result, double a, double b){
result = a/b;
}
希望这有助于您理解问题。
答案 1 :(得分:0)
要调用class计算中的任何方法,您必须先声明一个变量,然后再调用该方法,例如:
calculate c;
double a,b,res;
c.addition(a,b,res);
或者您将方法定义为静态函数,在这种情况下,调用将像这样
calculate::addition(a,b,res);