Question

我尝试扩展照明类翻译器

我创建了一个类并扩展到翻译器然后将这行添加到我的RepositoryServiceProvider

$this->app->bind(\Illuminate\Translation\Translator::class, \App\Repositories\Translation\TranslationTranslator::class);

但是它不起作用

我在做什么错了？

该类如下

<?php

namespace App\Repositories\Translation;

use Countable;
use Illuminate\Support\Arr;
use Illuminate\Support\Str;
use Illuminate\Support\Collection;
use Illuminate\Support\Traits\Macroable;
use Illuminate\Support\NamespacedItemResolver;
use Symfony\Component\Translation\MessageSelector;
use Symfony\Component\Translation\TranslatorInterface;


class TranslationTranslator extends \Illuminate\Translation\Translator
{
    /**
     * Parse a key into namespace, group, and item.
     *
     * @param  string  $key
     * @return array
     */
    public function parseKey($key)
    {
        \Log::info('got in');
        die;
        $segments = parent::parseKey($key);

        if (is_null($segments[0])) {
            $segments[0] = @explode('.', $segments[2])[0];
        }
        if ($segments[1] == 'translatable') {
            $segments[1] = @explode('.', $segments[2])[0] . '_' . @explode('.', $segments[2])[1];
        }
        return $segments;
    }
}

更新

显然Translator类具有构造函数

 public function __construct(LoaderInterface $loader, $locale)
    {
        $this->loader = $loader;
        $this->locale = $locale;
    }

所以我的绑定必须通过该接口..无法实例化

 public function boot()
{
    $app = $this->app;
    $this->app->bind(\Illuminate\Translation\Translator::class, function() use ($app){
        return $app->make(\App\Repositories\Translation\TranslationTranslator::class);
    });        
}

并收到此错误

带有消息的Illuminate \ Contracts \ Container \ BindingResolutionException '目标[Illuminate \ Translation \ LoaderInterface]无法实例化在构建[App \ Repositories \ Translation \ TranslationTranslator]时。”

Answer 1

您可以使用闭包来解析类

$this->app->bind(\Illuminate\Translation\Translator::class, function(){

    return new \App\Repositories\Translation\TranslationTranslator;
});

第二个翻译器使用translator别名与laravel绑定。

您也可以覆盖它。

$this->app->bind('translator', function(){
        return new \App\Repositories\Translation\TranslationTranslator; 
    })

Answer 2

这对我有用

$app = $this->app;
$loader = $app['translation.loader'];
$locale = $app['config']['app.locale'];

$this->app->bind('translator', function() use ($loader, $locale){
    return new \App\Repositories\Translation\TranslationTranslator($loader, $locale);
});

希望对您有帮助

Answer 3

检查以下示例

namespace App\Repositories\Translation;

use Illuminate\Translation\Translator;
class TranslationTranslator extends Translator
{

    public function get()
    {
        ....
    }
}

不需要任何东西。您只需要添加新功能或覆盖基类功能。然后，您可以将该类用作简单的其他类。

Laravel扩展供应商类别

3 个答案: