APEX 5 ORACLE SQL中带有动态魔术支点的错误“此处仅允许简单列名”

时间:2018-09-13 11:05:18

标签: sql oracle pivot oracle-apex

我尝试在Oracle APEX 5中构建PIVOT表。我有3个表:

表CAB
身份证号码
CAB_DATE DATE

表CAB_DEP_TO_CAB
CAB_ID VARCHAR2
DEP_ID VARCHAR2

表CAB_DEP
身份证号码
DEP_NAME VARCHAR2

我尝试过:

SELECT DISTINCT 
    LISTAGG('''' || CAB_DATE || ''' AS ' || CAB_DATE,',')
        WITHIN GROUP (ORDER BY CAB_DATE) AS temp_in_statement 
    FROM (SELECT DISTINCT CAB_DATE FROM CAB);

这没问题,但PIVOT没问题

SELECT * FROM 
    (SELECT cd.dep_name, c.cab_date, d.dep_id FROM cab c INNER JOIN cab_dep_to_cab d ON c.id = d.cab_id INNER JOIN cab_dep cd ON d.dep_id like ('%' || cd.id || '%') )
    PIVOT (SUM(dep_id) FOR c.cab_date IN (&str_in_statement));

它返回错误:ORA-01748“此处仅允许使用简单的列名”

有人可以看到我的错误吗? :O

顺便说一句。我想要这样的结果: enter image description here

顺便说一句。我试图从此处使用代码:Dynamic pivot in oracle sql

1 个答案:

答案 0 :(得分:1)

我认为这里的问题是,您在数据透视功能中使用的是“ c.cab_date”而不是“ cab_date”。这应该可以工作(不确定为什么在第二个联接上有如此奇怪的联接条件,我用一个更合理的联接条件代替了它):

SELECT * FROM 
    (SELECT cd.dep_name
          , c.cab_date
          , d.dep_id
       FROM cab c 
      INNER JOIN cab_dep_to_cab d ON c.id = d.cab_id 
      INNER JOIN cab_dep cd ON d.dep_id = cd.id
    )
 PIVOT (SUM(dep_id) FOR cab_date IN (&str_in_statement));

如果我可以为您的表设计添加一些小提示:我建议将“部门ID”之类的列命名为始终相同,这将使代码更具可读性,但这只是出于个人喜好。当然;)

我用这种方式命名事物:

Table CAB
CAB_ID number
CAB_DATE date

Table DEPARTMENTS
DEPARTMENT_ID number
DEPARTMENT_NAME varchar2

Table DEPARTMENT_CABS
CAB_ID number  -- not varchar as in your example!
DEPARTMENT_ID number  -- not varchar as in your example!