Question

我有三个数组。 1.现有查看者数组-existingViewers

新观众数组-newViewers
允许的查看者数组-permittedViewers

permittedViewers用于呈现下拉列表。我希望从newViewers过滤existingViewers和permittedViewers条目。

我正在按照三个步骤进行操作。而且恐怕这不是优化的方法。有人可以建议这样做的理想方法吗？预期结果是

[
  {
    "id": 4,
    "name": "name4"
  },
  {
    "id": 5,
    "name": "name5"
  },
  {
    "id": 6,
    "name": "name6"
  }
]

let existingViewers = [{
      "viewerId": 1,
      "name": "name1"
    },
    {
      "viewerId": 2,
      "name": "name2"
    }
  ],
  newViewers = [

    {
      "viewerId": 3,
      "name": "name3"
    }
  ],
  permittedViewers = [{
      "id": 1,
      "name": "name1"
    },
    {
      "id": 2,
      "name": "name2"
    },
    {
      "id": 3,
      "name": "name3"
    },
    {
      "id": 4,
      "name": "name4"
    },
    {
      "id": 5,
      "name": "name5"
    },
    {
      "id": 6,
      "name": "name6"
    }
  ]
let grouped = [...existingViewers, ...newViewers]

let viewerFilter = grouped.map(viewer => { return viewer.viewerId; });

let filteredPermittedViewers = permittedViewers.filter(viewer => !viewerFilter.includes(viewer.id));

console.log(filteredPermittedViewers)

Answer 1

您可以将所有三个语句压缩为一个语句-只需用创建它的语句替换变量名：

let existingViewers = [{
      "viewerId": 1,
      "name": "name1"
    },
    {
      "viewerId": 2,
      "name": "name2"
    }
  ],
  newViewers = [

    {
      "viewerId": 3,
      "name": "name3"
    }
  ],
  permittedViewers = [{
      "id": 1,
      "name": "name1"
    },
    {
      "id": 2,
      "name": "name2"
    },
    {
      "id": 3,
      "name": "name3"
    },
    {
      "id": 4,
      "name": "name4"
    },
    {
      "id": 5,
      "name": "name5"
    },
    {
      "id": 6,
      "name": "name6"
    }
  ]

let filteredPermittedViewers = permittedViewers.filter(viewer => ! [...existingViewers, ...newViewers].map(viewer => viewer.viewerId).includes(viewer.id));

console.log(filteredPermittedViewers)

根据多个数组输入过滤一个数组

1 个答案: