我正在通过ASP.NET-MVC开发Web应用程序。
型号:
[Display(Name = "REGISTERED ADDRESS")]
[StringLength(255)]
public string ADDRESS { get; set; }
HTML:
@Html.TextBox("textBoxFillToAnothertextBox", null, new { id = "textBoxFillToAnothertextBox", @class = "form-control", placeholder = "Fill in to apply for textBoxAddress" })
@Html.TextBoxFor(m => m.ADDRESS, new { id = "textBoxAddress" + i, @class = "form-control" })
@Html.ValidationMessageFor(m => m.ADDRESS, "", new { @class = "text-danger" })
jQuery:
$('#textBoxFillToAnothertextBox').on('keyup change', function () {
$('#textBoxAddress').val($('#textBoxFillToAnothertextBox').val());
});
情况1:我将文本填充到“ textBoxAddress”。文本长度超过255,然后正常显示“ ValidationMessage of Address”。
情况2:我将文本填充到由jQuery设置为“ textBoxAddress”的“ textBoxFillToAnothertextBox”。文本长度超过255,则不会显示“ ValidationMessage of Address”。
在第二种情况下,有人可以帮我推荐吗?
答案 0 :(得分:2)
使用maxlength
属性:
@Html.TextBox("textBoxFillToAnothertextBox", null, new { id = "textBoxFillToAnothertextBox",maxlength = 250 , @class = "form-control", placeholder = "Fill in to apply for textBoxAddress" })
或
$('#textBoxFillToAnothertextBox').on('keyup change', function() {
if ($('#textBoxFillToAnothertextBox').val().length > 250) {
$('#ADDRESS').text('error message');
} else {
$('#textBoxAddress').val($('#textBoxFillToAnothertextBox').val());
}
});
答案 1 :(得分:0)
目前,我使用@StephenMuecke中的概念。
jQuery:
#include <iostream>
using namespace std;
int main(void)
{
int x;
int count = 0;
int N;
double sum = 0;
double average;
char ans = 'Y';
cout << "Enter number of values, N, to be read in <Enter>:" << endl;
cin >> N;
do
{
if(N > 0){ //THIS IF STATEMENT WILL ALWAYS RUN AT LEAST ONCE
cout << "\n Enter a grade <Enter>: ";
cin >> x;
sum = sum + x;
count++;
}
if(count == N && N != 0) {//THIS IF STATEMENT WILL ALSO ALWAYS RUN AT LEAST ONCE
average = average = sum / N;
cout << "The average of these " << N << " grades is " << average << endl;
cout << "Would you like to enter more values to calculate your grade average?\n";
cin>>ans;
if(ans == 'Y') {//This one depends on it's parents result.
x = 0;
N = 0;
sum = 0;
count = 0;
cout << "Enter number of values, N, to be read in <Enter>:" << endl;
cin >> N;
}
}
} while (ans == 'Y' && N != 0);
if (N == 0)
cout << "You have entered 0 numbers. No average will be computed. Bye! \n";
system("pause");
return 0;
}
这对我有用。