这是一个简单的游戏，其中有23个木棍，您和计算机可以删除1、2或3，而删除最后一个的人将丢失。正如您可能想象的那样，这是一个课堂项目。
完整代码为here。
#include <iostream>
#include <cstdlib>
using namespace std;
int main()
{
char playAgain = 'Y';
int totalSticks = 23;
int humanStickChoice = 1;
cout<<"**************************** RULES: Remove 1, 2, or 3 sticks per turn.\n";
cout<<"*Welcome to our Game of 23!* The player who removes the very last stick\n";
cout<<"**************************** loses. Good luck!\n";
cout<<endl;
while (totalSticks > 0 && playAgain == 'Y' || playAgain == 'y')
{
cout<<"There are "<<totalSticks<<" sticks left. How many sticks would you like to remove?:\n";
cin>>humanStickChoice;
cout<<endl;
if(totalSticks >= 3){
if(humanStickChoice != 1 && humanStickChoice != 2 && humanStickChoice != 3){
while(humanStickChoice != 1 && humanStickChoice != 2 && humanStickChoice != 3){
cout<<"Invalid choice; you can remove 1, 2, or 3 sticks. Choose again:\n";
cin>>humanStickChoice;
}
}
totalSticks=totalSticks-humanStickChoice;
cout<<"Player removes "<<humanStickChoice<<" sticks.\n";
}
else if(totalSticks == 3){
if(humanStickChoice != 1 && humanStickChoice != 2){
while(humanStickChoice != 1 && humanStickChoice != 2){
cout<<"Invalid choice; you can remove 1 or 2 sticks. Choose again:\n";
cin>>humanStickChoice;
}
}
}
else if(totalSticks == 2){
if(humanStickChoice != 1){
while(humanStickChoice != 1){
cout<<"Invalid choice; as there are 2 sticks remaining, you can remove only one.\n";
cin>>humanStickChoice;
}
}
totalSticks=totalSticks-humanStickChoice;
cout<<"Player removes "<<humanStickChoice<<" sticks.\n";
}
else if(totalSticks == 1){
if(humanStickChoice != 1){
while(humanStickChoice != 1){
cout<<"Invalid choice; as there is 1 stick remaining, you can remove only one.\n";
cin>>humanStickChoice;
}
}
int humanStickChoice = 1;
cout<<"Player removes "<<humanStickChoice<<" stick.\n";
totalSticks=totalSticks-humanStickChoice;
cout<<"*************************************************\n";
cout<<"Player removed the last stick! Computer wins!";
if(totalSticks == 0){
cout<<endl<<"Would you like to play again? If so, input Y and hit return.\n";
cin>>playAgain;
totalSticks = 23;
}
}
//This block above is where the logic error is occurring; instead of going back to the
//beginning of the "main" while loop and starting over with the human player starting,
//the totalSticks count is merely replenished and the program continues to go on with the
//computer making the first move; the human is supposed to make the first move every game.
if(totalSticks > 4){
int computerStickChoice = (4-humanStickChoice);
cout<<"Computer removes "<<computerStickChoice<<" sticks.\n";
totalSticks=totalSticks-computerStickChoice;
}
else if(totalSticks == 4){
int computerStickChoice = 3;
cout<<"Computer removes "<<computerStickChoice<<" sticks.\n";
totalSticks=totalSticks-computerStickChoice;
}
else if(totalSticks == 3){
int computerStickChoice = 2;
cout<<"Computer removes "<<computerStickChoice<<" sticks.\n";
totalSticks=totalSticks-computerStickChoice;
}
else if(totalSticks == 2){
int computerStickChoice = 1;
cout<<"Computer removes "<<computerStickChoice<<" stick.\n";
totalSticks=totalSticks-computerStickChoice;
}
else if(totalSticks == 1){
int computerStickChoice = 1;
cout<<"Computer removes "<<computerStickChoice<<" stick.\n";
totalSticks=totalSticks-computerStickChoice;
cout<<"*************************************************\n";
cout<<"Computer removed the last stick! You win!";
if(totalSticks == 0){
cout<<endl<<"Would you like to play again? If so, input Y and hit return.\n";
cin>>playAgain;
totalSticks = 23;
}
}
}
return 0;
}
导致错误的部分：
else if(totalSticks == 1){
if(humanStickChoice != 1){
while(humanStickChoice != 1){
cout<<"Invalid choice; as there is 1 stick remaining, you can ";
"remove only one.\n";
cin>>humanStickChoice;
}
}
int humanStickChoice = 1;
cout<<"Player removes "<<humanStickChoice<<" stick.\n";
totalSticks=totalSticks-humanStickChoice;
cout<<"*************************************************\n";
cout<<"Player removed the last stick! Computer wins!";
if(totalSticks == 0){
cout<<endl<<"Would you like to play again? If so, input Y and hit
return.\n";
cin>>playAgain;
totalSticks = 23;
}
}
我调试了每种情况（我认为），这些嵌套循环可能会中断，除了我不知道的情况。
我已经在其上方添加了注释行以进行解释，但我也会在此处进行解释；当玩家在最后一个else-if区块中输了球时，将补充摇杆的数量，并提供cin输入以询问用户是否要玩其他游戏。应该重新开始，让他们扮演第一步，但是，只是继续编写代码，让计算机迈出第一步。
我如何让人类再次迈出第一步？
我尝试使用break;并弄乱了“主要”的while循环要求，但我做对了。
答案 0 :(得分：0)
使用continue跳过循环主体的其余部分，并立即进行下一次迭代。
使用break完全退出循环。所以最终的测试应该是：
if(totalSticks == 0){
cout<<endl<<"Would you like to play again? If so, input Y and hit
return.\n";
cin>>playAgain;
if (playAgain == 'y' || playAgain == 'Y') {
totalSticks = 23;
continue;
} else {
break;
}
}
有了此更改，也无需在playAgain条件下测试while。这里的测试可以完全处理它。
答案 1 :(得分：0)
时间紧迫，所以不是最理想的方法，但这是代码：
humanFirstMove = false;
cout << "There are " << totalSticks << " sticks left. How many sticks would you like to remove?:\n";
cin >> humanStickChoice;
cout << endl;
和
if (totalSticks == 0) {
cout << endl << "Would you like to play again? If
so, input Y and hit return.\n";
cin >> playAgain;
totalSticks = 23;
humanFirstMove = true;
}
最后
//This block above is where the logic error is
occurring;instead of going back to the
//beginning of the "main" while loop and starting over with the human player starting,
//the totalSticks count is merely replenished and the program continues to go on with the
//computer making the first move; the human is supposed to make the first move every game.
if (!humanFirstMove) {
if (totalSticks > 4) {
int computerStickChoice = (4 - humanStickChoice);
cout << "Computer removes " << computerStickChoice << " sticks.\n";
totalSticks = totalSticks - computerStickChoice;
}
几乎刚刚添加了一个布尔值