Question

我有以下代码，并且工作正常：

$time = time(); 
$todayint=date("Y-m-d", strval($time));

    $sql = "SELECT * FROM " . $DB->prefix('cal_event') . " WHERE DATE(FROM_UNIXTIME(event_start))='$todayint' OR DATE(FROM_UNIXTIME(event_end))='$todayint' ORDER BY event_organiser ASC";

如何更改代码以选择日期范围内的数据？

event_start和event_end存储为整数。

我尝试使用between，但是我不确定在代码之间的确切位置。

Answer 1

对于单个日期字段的查询，可以使用 BETWEEN 运算符：

$sql = "SELECT * FROM " . $DB->prefix('cal_event') . " WHERE 
        DATE(FROM_UNIXTIME(event_time)) BETWEEN '$date1' AND '$date2'
        ORDER BY event_organiser ASC";

对于针对多个日期字段（例如开始时间和结束时间）的查询，您需要检查=>和<=：

$sql = "SELECT * FROM " . $DB->prefix('cal_event') . " WHERE 
        DATE(FROM_UNIXTIME(event_start)) >= '$todayint' AND
        DATE(FROM_UNIXTIME(event_end)) <= '$todayint'
        ORDER BY event_organiser ASC";

在两种情况下，您都希望使用AND而不是OR。

Answer 2

使用BETWEEN（column BETWEEN value1 AND value2）

$time = time(); 
$todayint=date("Y-m-d", strval($time));

$sql = "SELECT * FROM " . $DB->prefix('cal_event') 
     . "WHERE DATE(FROM_UNIXTIME(event_start))
        BETWEEN '$todayint' AND '$todayint'
        ORDER BY event_organiser ASC";

使用>=（column >= value1 AND column <= value2）

$time = time(); 
$todayint=date("Y-m-d", strval($time));

$sql = "SELECT * FROM " . $DB->prefix('cal_event') 
     . "WHERE DATE(FROM_UNIXTIME(event_start)) >= '$todayint'
        AND DATE(FROM_UNIXTIME(event_end)) <= '$todayint'
        ORDER BY event_organiser ASC";

更改SQL查询以查找日期范围之间的数据

2 个答案: