Question

我有一个很大的文件（仅用于流式传输），并且想将其上传到我的REST WCF服务中：

    [OperationContract]
    [WebInvoke(Method = "POST", UriTemplate = "upload?name={name}&tags={tags}&storage={storage}")]
    UploadFileResponse UploadFile(string name, string tags, string storage, Stream file);

这是我使用RestSharp的方法：

    private void Upload(string filePath)
    {
        var name = Path.GetFileName(filePath);

        var client = new RestClient(_endpoint);
        client.Proxy = null;

        var req = new RestRequest("upload", Method.POST);
        req.AlwaysMultipartFormData = true;
        req.AddQueryParameter("name", name);
        if (_tags.Any())
        {
            req.AddQueryParameter("tags", string.Join(";", _tags));
        }
        req.AddQueryParameter("storage", _targetStorage);
        //req.AddFile(name, filePath, "application/x-binary");

        req.Files.Add(new FileParameter
        {
            Name = "file",
            Writer = (s) =>
            {
                using (var stream = File.OpenRead(filePath))
                {
                    stream.CopyTo(s);
                }
            },
            FileName = name,
            ContentLength = new FileInfo(filePath).Length,
        });
        var response = client.Execute<UploadFileResponse>(req);
        response.ThrowIfError();

        var result = response.Data;
    }

这是我在发送简单文本文件时从服务器上的流中获取的信息：

-------------------------------28947758029299
Content-Disposition: form-data; name="file"; filename="test.txt"
Content-Type: application/octet-stream

tttttttttttttttt  <==== this is text I sent
-------------------------------28947758029299--

如何删除此多部分垃圾内容？是否存在某种可以读取此格式的流包装器？我应该如何处理呢？

如何从POST WCF方法中删除多部分垃圾？

0 个答案: