考虑以下代码和输出
代码1 :
ls = ["one is one","two is two","three is three"]
for each_item in ls:
print(each_item)
输出1:
代码2:
ls = ["one is one","two is two","three is three"]
for each_item in ls:
for each_word in each_item:
print(each_word)
输出2:
我的意图是打印如下
一个
是
一个
两个
是
两个
三个
是
三个
在哪里需要修改以按期望的顺序打印?
答案 0 :(得分:1)
根据taoufik的评论,您想在迭代每个句子之前split。这是因为,默认情况下,当您在Python中遍历字符串时,它将逐字符进行。通过调用split
,您可以将字符串(按空格)分成单词列表。见下文。
ls = ["one is one","two is two","three is three"]
for sentence in ls:
for word in sentence.split():
print(word)
one
is
one
two
is
two
three
is
three
答案 1 :(得分:1)
尝试一下:
ls = ["one is one","two is two","three is three"]
words = []
for each_item in ls:
words = each_item.split()
for word in words:
print(word)