Question

我正在尝试从联合查询中获取所需的内容，并正确使用值作为数组键，以便我可以正确地构建一些DIV列表

我的php查询和数组：

$getTickers = "
    SELECT d.ID as displayID, d.display_name as display, l.location_name as locationName, d.location_id as location, t.id as ticker, tc.id as contentID, tc.content
        FROM displays d
            INNER JOIN locations l on d.location_id = l.id
            INNER JOIN tickers t on d.id = t.display_id
            INNER JOIN ticker_content tc on t.id = tc.ticker_id;
";

$tickers = $mysqlConn->query($getTickers);

$tickerDisplays = array();
foreach($tickers as $subArray) {
    if(!array_key_exists($subArray['displayID'], $tickerDisplays)) {
        $tickerDisplays[$subArray['displayID']] = array();

    }
    // here you add `display_name` under key `display_id`
    $tickerDisplays[$subArray['displayID']][$subArray['location']] = $subArray['display'];
}

下面的所有示例和代码，但我不需要html结构的帮助，只是如何重组数组/键以提供所需的结果以及如何在前端循环它们。

我现在正按预期获得4个div（每个唯一的显示/位置一个）但是我需要弄清楚如何正确安排它，以便可以将DIsplay名称呼应为h4，将位置呼应为h5，然后在列表中回显每个内容

所以查询结果给了我这个

displayID | display |  locationName  | location | ticker | contentID |    content         | 

  1         Office      Building 4       4         1          1         testing content
  2         Lobby       Building 4       4         2          2         testing content 2
  3         Lobby       Building 1       1         3          3         testing content 3
  4         Office      Building 1       1         4          4         testing content 4
  4         Office      Building 1       1         4          5         testing content again

我正在尝试以此为目标，使每个位置/显示组合都有一个div的预期结果，像这样：

OFFICE           
Building 4

testing content

---------------

LOBBY           
Building 4

testing content 2

------------------

LOBBY           
Building 1

testing content 3

------------------


OFFICE 
Building 1

testing content 4
testing content again

----------------------

这是我目前试图循环播放的方式

<?php foreach($tickerDisplays as $key => $ticker):?>

        <h4><?php echo $key ?></h4>     //so this should be the display Name (office, lobby)
        <h5><?php echo //location?></h5> //this should be the location name (Building 1, Building 4)

        //This will be another foreach for any content associated with the location/display
        <ul class="tickerContent">
            <li>
        </ul>
      </div>
    </div>
<?php endforeach;?>

Answer 1

这里的方法是为每个显示行创建一个子数组以包含所有多个内容记录。

// Dummy the data from the query
$tickers = [

['displayID' => 1,          'display' => 'Office',      'locationName' => 'Building 4',        'location' => 4,          'ticker' => 1,          'contentID' => 1,          'content' => 'testing content'],
['displayID' => 2,          'display' => 'Lobby',       'locationName' => 'Building 4',        'location' => 4,          'ticker' => 2,          'contentID' => 2,          'content' => 'testing content 2'],
['displayID' => 3,          'display' => 'Lobby',       'locationName' => 'Building 1',        'location' => 1,          'ticker' => 3,          'contentID' => 3,          'content' => 'testing content 3'],
['displayID' => 4,          'display' => 'Office',      'locationName' => 'Building 1',        'location' => 1,          'ticker' => 4,          'contentID' => 4,          'content' => 'testing content 4'],
['displayID' => 4,          'display' => 'Office',      'locationName' => 'Building 1',        'location' => 1,          'ticker' => 4,          'contentID' => 5,          'content' => 'testing content again']
];

// A place to keep the reorganized data
$tickerDisplays = [];

// Walk through the query result
foreach($tickers as $row) {
    $displayID = $row['displayID']; // for convenience and readability
    $location = $row['location'];   // for convenience and readability
    $display = $row['display'];
    $contentID = $row['contentID'];

    if ( ! array_key_exists($row['displayID'], $tickerDisplays) ) {
        $tickerDisplays[$displayID] = [
            'displayID' => $row['displayID'],
            'display' => $row['display'],
            'ticker' => $row['ticker'],
            'contentID' => $row['contentID'],
            'content' => $row['content'],
            'location' => $row['location'],
            'locationName' => $row['locationName'],
            '@content' => [] // to store the content data                
        ];

    }
    $tickerDisplays[$displayID]['@content'][$contentID] = ['content' => $row['content']];
}

print_r($tickerDisplays);

foreach ( $tickerDisplays as $key => $ticker ) {
    // Output the display and location name
    out($ticker['display']);
    out($ticker['locationName']);
    // Output all the content records.
    foreach ( $ticker['@content'] as $contentID => $content ) {
        out($content['content']);
    }
    out('------------');
}
// Just a utility function
function out($msg) {
    echo "$msg\n";
}

输出：

Office
Building 4
testing content
------------
Lobby
Building 4
testing content 2
------------
Lobby
Building 1
testing content 3
------------
Office
Building 1
testing content 4
testing content again
------------

从SQL查询重组数组，以便我可以回显正确的值

1 个答案: