Question

我想用JAXB创建一个通用的xmlFileValidator，该XMLFileValidator接受一个XML文件和一个模式文件，如果该文件有效，则返回根类的对象，否则抛出SAXException或JAXBException。

public class XmlValidateEventHandler implements ValidationEventHandler {
public static <E> void validator(File xsdFile, File xmlFile, E obj) throws SAXException, JAXBException
{
    JAXBContext jaxbcontextobj = JaxbUtil.create_context_obj(new ObjectFactory());
    SchemaFactory sf = SchemaFactory.newInstance(XMLConstants.W3C_XML_SCHEMA_NS_URI);
    Schema schema = sf.newSchema(xsdFile);
    Unmarshaller unmarshaller = JaxbUtil.create_unmarshl_obj(jaxbcontextobj);

    unmarshaller.setSchema(schema);
    unmarshaller.setEventHandler(new XmlValidateEventHandler());        
    javax.xml.bind.JAXBElement<Document>  doc = (javax.xml.bind.JAXBElement<Document>) unmarshaller.unmarshal(xmlFile);
    Document d = doc.getValue();
    obj=(E)d;
}

@Override
public boolean handleEvent(ValidationEvent event) {

    Logger logger = utility.JaxbUtil.getLogger();
    if(event.getSeverity() == ValidationEvent.ERROR || event.getSeverity() == ValidationEvent.FATAL_ERROR)
    {                           
        //Logger logger = Logger.getLogger(XmlValidateEventHandler.class);              
        logger.error("SEVERITY:  " + event.getSeverity());          
        logger.error("MESSAGE:  " + event.getMessage());            
        logger.error("LINKED EXCEPTION:  " + event.getLinkedException());           
        logger.error("LINE NUMBER:  " + event.getLocator().getLineNumber());
        logger.error("COLUMN NUMBER:  " + event.getLocator().getColumnNumber());
        logger.error("***** Give XML is invalid aginst given XSD *****");
        return false;
    }   
}

}

以下行给出警告->

类型安全性：未经检查的从Object到JAXBElement的投射

javax.xml.bind.JAXBElement<Document>  doc=(javax.xml.bind.JAXBElement<Document>) unmarshaller.unmarshal(xmlFile);

而且我也无法映射未编组的对象并将其设置为在参数中传递的 E obj 。我知道它可以返回，但已被要求将其设置为该参数。请帮忙。预先感谢

Answer 1

我更改为以下内容，并且有效：

    public static <E> E validator(File xsdFile, File xmlFile, E obj) throws SAXException, JAXBException
{   
    JAXBContext jaxbcontextobj = JaxbUtil.setContextObj(new ObjectFactory());
    SchemaFactory sf = SchemaFactory.newInstance(XMLConstants.W3C_XML_SCHEMA_NS_URI);
    Schema schema = sf.newSchema(xsdFile);
    Unmarshaller unmarshaller = JaxbUtil.setUnmarshlObj(jaxbcontextobj);

    unmarshaller.setSchema(schema);
    unmarshaller.setEventHandler(new XmlValidateEventHandler());        
    javax.xml.bind.JAXBElement<E>  doc = (javax.xml.bind.JAXBElement<E>) unmarshaller.unmarshal(xmlFile);
    E d = (E) doc.getValue();
    return d;
}

但是现在仍然有开放性： 1.我仍然无法将对象映射到第三个参数-> E obj 2.我正在使用JAXB生成的类中的ObjectFactory：

导入XmlClasses.ObjectFactory;

哪些仍不能使其完全通用，如何采用通用ObjectFactory？

针对XML模式（XSD文件）的通用XML文件验证器

1 个答案: