Question

我具有函数findFlightRecommendation的功能。它返回Flight类型。

export const findFlightRecommendation = <T>(state: IStore, sectorIds: T): Flight => {
  if (!state || !state.search || !state.search.results) {
    return undefined
  }
  ...
  return state.search.results.find(r => _.isEqual(r.sectorsId, sectorIds))
}

此功能用于查找航班：

// state.personalData.sectorsKey is string[]
const flight = findFlightRecommendation(state, state.personalData.sectorsKey)

此flight对象后来在其他函数上用作参数。

formatLoadingSubtitle(props.t, flight, getTravellers(state.form.searchForm.values)

但是formatLoadingSubtitle类型声明说，排期应为HasSectors：

export const formatLoadingSubtitle = (t: Translate, flight: HasSectors, travellers: number) => {
  const departure = getDepartureTime(flight)
  const arrival = getReturnTime(flight)

  if (departure) {
    return formatFlightDetails(t, departure, arrival, travellers)
  }
}

类型：

export interface Flight extends BasicFlightInfo {
  mtk?: boolean
  sectorsId?: string[]
  sectorCodes?: string[]
  handBaggage?: IHandBaggage
  checkedBaggageIncluded?: boolean
  leftSeats?: number
  topRecommendationTag?: FilterSortByTypes
  recommendationPriority?: number
}

export interface BasicFlightInfo extends HasSectors, FlightDebugInfo {
  totalPrice: number
  paxPrices: IPaxPrices
  currency: string
  offerFees: IOfferFees
  totalDiscount?: number
  cabinClasses?: string[]
}

interface HasSectors {
  sectors: ISector[]
}

Answer 1

没有问题，因为实现Flight接口的每个对象还通过通过HasSectors的继承来实现BasicFlightInfo。

这意味着只要期望使用HasSectors，就可以使用任何实现它的对象（即，任何实现HasSectors，BasicFlightInfo或Flight的对象）。

一切正常，没有“类型不匹配”。

打字稿未检测到类型错误

1 个答案: