在以下情况下使用选择和大小写获取输出

Question

我正在尝试以以下格式显示输出：

错误：

致命错误：mysqli_sql_exception未捕获：SQL语法有错误；检查与您的MySQL服务器版本相对应的手册以获取正确的语法，以在'附近使用minrange，以sum（case，当DATE（holddate）= CURDATE（））作为holddate，以sum（case'at

代码：

<?php

$sql =

"select 
sum(case when DATE(reattemptdate) = CURDATE()) as minrange,
sum(case when DATE(holddate) = CURDATE()) as holddate,
sum(case when DATE(reattemptdate) = DATE(NOW() - INTERVAL 1 DAY)) as prev_reattemptdate,
sum(case when DATE(holddate) = DATE(NOW() - INTERVAL 1 DAY)) as prev_holddate
from orders
 ";
$results = $db_handle->runSelectQuery($sql); 
$numrowsresult =$results[0]['count'];  
echo $numrowsresult;

?>

Answer 1

我需要这个：THEN 1 ELSE 0 END

select sum(case when DATE(reattemptdate) = CURDATE() THEN 1 ELSE 0 END) as reattemptdate,
       sum(case when DATE(holddate) = CURDATE() THEN 1 ELSE 0 END) as holddate,
       sum(case when DATE(reattemptdate) = DATE(NOW() - INTERVAL 1 DAY) THEN 1 ELSE 0 END) as prev_reattemptdate,
       sum(case when DATE(holddate) = DATE(NOW() - INTERVAL 1 DAY) THEN 1 ELSE 0 END) as prev_holddate
from orders;

Answer 2

您有一个CASE WHEN，但您从未指定THEN（和ELSE）。

因此语法缺少一些内容。