Question

var secretWord = [];
var underScoreWord = [];
// var guesses = [];
var wordLetter = false;

var city = ["Paris", "Wellington", "Hanoi", "Perth", "Marseille", "London", "Ottawa", "Zurich", "Boston", "Tokyo", "Detroit"];

// console.log(city);

// Pick random word from the team array and push the result to an empty array. 
// FUNCTION 1 pick random city
function pickRandomCity() {
    var randomCity = city[Math.floor(Math.random() * city.length)];
    secretWord.push(randomCity);
    return randomCity;
}

var cityPicked = pickRandomCity();

// Get length of secretWord and push as underscores to am empty array
for (var i = 0; i < cityPicked.length; i++) {
underScoreWord.push("_");
}

console.log(secretWord);
console.log(underScoreWord);



// Check for letters
//listen for key press and check to see if its a match
document.onkeyup = function letterCheck(event) {
    var userGuess = event.key;  
  
    for (var j = 0; j < cityPicked.length; j++) {
        if (userGuess === cityPicked[j]) {
            wordLetter = true;
        }
        if (wordLetter) {
        underScoreWord.push(userGuess);
        }
    }



    console.log(wordLetter);
    

}

在onkeyup函数内部，我试图将结果（按下的键）推入underScoreWord数组。当我键入正确的键时，它会将wordLetter布尔值转换为true，但我不知道如何将其推入显示在单词中，因此它显示如下_ _ N _ _ _

我想我很近，但是我可能又相距甚远。有提示吗？

Answer 1

您要通过按_数组中匹配的单词按下键来填充underScoreWord值

示例：

如果东京被选为居住城市，
它将[ "_", "_", "_", "_" ]存储在underScoreWord
现在，如果按T，它将填充到[ "T", "_", "_", "_" ]
在使用后按o，它将填充到[ "T", "o", "_", "o" ]

问题：


secretWord是数组，但以1个长度存储整个单词

仅在underScoreWord中填充正确拼写匹配的相同索引

请检查以下解决方案：

var secretWord = [];
var underScoreWord = [];
var guesses = [];
var wordLetter = false;

var city = ["Paris", "Wellington", "Hanoi", "Perth", "Marseille", "London", "Ottawa", "Zurich", "Boston", "Tokyo", "Detroit"];

// Pick random word from the team array and push the result to an empty array. 
// FUNCTION 1 pick random city
function pickRandomCity() {
    var randomCity = city[Math.floor(Math.random() * city.length)];
    secretWord  = randomCity.split('');
            
    return randomCity;
}

var cityPicked = pickRandomCity();

// Get length of secretWord and push as underscores to am empty array
for (var i = 0; i < cityPicked.length; i++) {
    underScoreWord.push("_");
}

console.log('secretWord : ' + secretWord);
console.log('underScoreWord : ' + underScoreWord);
console.log('------------------');
console.log('cityPicked : ' + cityPicked);



// Check for letters
//listen for key press and check to see if its a match
document.onkeyup = function letterCheck(event) {
    var userGuess = event.key;
    for (var j = 0; j < secretWord.length; j++) {
        if (userGuess === secretWord[j]) {
            wordLetter = true;
            underScoreWord[j]= userGuess;
        }
    }
    console.log(underScoreWord);
}

Answer 2

尝试这个

替换此

underScoreWord.push(userGuess);

为此

underScoreWord[j] = userGuess

Answer 3

您无需将字母推到underScoreWord上。只需将相应的下划线替换为字母即可。

for (var j = 0; j < cityPicked.length; j++) {
    if (userGuess == cityPicked[j]) {
        underScoreWord[j] = userGuess;
    }
}

我在将值附加到数组时遇到问题

3 个答案: