Question

我有以下简单实体：

Suggestion.java：

@Entity
public class Suggestion {

    @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    private long id;

    @OneToOne
    private Employee author;

    @OneToMany
    @JoinColumn(name = "recipients_id")
    private List<Employee> recipients;
}

和Employee.java：

@Entity
public class Employee {

    @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    private long id;

    private String name;
}

我想在控制器中返回所有suggestions，其中id列表中仅包含一个雇员的recipients。

是否可以避免自定义查询（本机查询）？

我尝试过：

findByRecipientsContains（id）或

findByRecipientsContaining（id）

但没有运气...

编辑：

在存储库中使用时：

Optional<List<Suggestion>> findByRecipientsIn(Long id);

也没有Optional并且在控制器中：

    @GetMapping("/employees/{id}/suggestions")
    @ResponseStatus(HttpStatus.OK)
    public List<Suggestion> getSuggestionsByRecipient(@PathVariable("id") Long id) {
        return suggestionRepository.findByRecipientsIn(id).get();
    }

我得到如下异常：

Parameter value element [1] did not match expected type [com.herokuapp.erpmesbackend.erpmesbackend.employees.Employee (n/a)]; nested exception is java.lang.IllegalArgumentException: Parameter value element [1] did not match expected type [com.herokuapp.erpmesbackend.erpmesbackend.employees.Employee (n/a)]] with root cause

Answer 1

这应该很简单

findByRecipientsId(Long id)

与此测试用例进行比较：https://github.com/spring-projects/spring-data-jpa/blob/688becd2b7129b853cd0deaf6bde3b50d9d8ce50/src/test/java/org/springframework/data/jpa/repository/UserRepositoryTests.java#L604

清单（JpaRepository）中包含“ id”的默认Spring Data查询

1 个答案: