Question

我是iOS的新手，我在应用中有一些Swift代码，该代码根据我从服务器收到的错误消息来切换大小写。邮件已包装好，我很难到达。这是代码

func sendAlamofireRequest(submissionURL: URL, parameters: Parameters, chosenTracker: String) -> String {

    var outputMessage = ""

    Alamofire.request(submissionURL, method: .post, parameters: parameters, encoding: JSONEncoding.default).validate().responseString() {
        response in
        switch response.result {
        case .success:
            print("Validation Successful...\(String(describing: response.value))")

            print("response value: \(String(response.value!))")
            switch response.value {
            case "error_none"?:
                outputMessage = "No matching Group Code. If you are having trouble, please go to \nhttps://app.phillyscientists.com"
                break
            case "error_tooManyIDs"?:
                outputMessage = "Error, please contact developer."
                break
            case "error_noGroupIDReceived"?:
                outputMessage = "Try Again."
                break
            default:

                let JSONResponse : JSON = JSON.init(parseJSON: response.result.value!)

                //uncomment this section for debugging
                //                        print("=================<JSON RESP>=================");
                //                        print(JSONResponse)
                //                        print("=================</JSON RESP/>=================");
                //
                let teacherNameGot = self.parseJSONData(json: JSONResponse, trackerValuePassed: chosenTracker)
                self.saveJSONDataToUserDefaults(teacher: teacherNameGot)

//                    outputMessage = "Logged In Successfully!"

                break
            }

        case .failure(let error):
            outputMessage = String(error.localizedDescription)
            print(outputMessage)

        }
    }
    return outputMessage
}

这是控制台的输出：

Validation Successful...Optional("{\"Error\":\"error_none\"}")
response value: Optional("{\"Error\":\"error_none\"}")

如何获得该值，以便开关盒真正开始工作？谢谢！

Answer 1

您可以使用Alamofire方法.responseJSON，该方法将为您提供一个http对象，该对象具有多个属性，例如request和response。以下面的代码为例：

Alamofire.request("https://your-service-url.com/api", method: .post, parameters: paremeters, encoding: JSONEncoding.default, headers: headers).responseJSON{ (data) in

            guard let statusCode = data.response?.statusCode, statusCode == 200, let result = data.result.value as? [[String: Any]] else{
                print("Error with HTTP status \(data.response?.statusCode ?? 0)")

                return
            }
            var events : [Event] = []
            result.forEach({ (rawEvent) in
                events.append(Event(from: rawEvent))
            })


            handler(events, statusCode)
    }

请注意，我如何在其中使用.responseJSON提供的对象，以及如何通过访问data.result.value从服务中获取结果数组（也就是说，这将取决于服务的数据结构响应）

Answer 2

输出似乎在Json中，因此我需要将其映射到一个对象（或类，无论您叫什么）。如果您认为它不值得，则可以将其转换为字典，我认为它也可以使用

Answer 3

@Gustavo caiafa是正确的，将其映射到JSON可以解决问题。这是任何陷入类似困境的人的代码：

Alamofire.request(submissionURL, method: .post, parameters: parameters, encoding: JSONEncoding.default).validate().responseString() { (response) in

        let outputResponseJSON : JSON = JSON.init(parseJSON: response.result.value!)
        let outputResponseText = JSON(outputResponseJSON)["Error"].stringValue

        switch response.result {
        case .success:
            print("Validation Successful...\(String(describing: response.value))")

            print("response value: \(String(describing: String(outputResponseText)))")
            switch outputResponseText {
            case "error_none":
                outputMessage = "No matching Group Code. If you are having trouble, please go to \nhttps://app.phillyscientists.com"
                print(outputMessage)
                break
            case "error_tooManyIDs":
                outputMessage = "Error, please contact developer."
                print(outputMessage)
                break
            case "error_noGroupIDReceived":
                outputMessage = "Try Again."
                print(outputMessage)
                break
            default:

                let JSONResponse : JSON = JSON.init(parseJSON: response.result.value!)

答案是使用SwiftyJSON作为outputResponseJSON和outputResponseText值。

如何访问alamofire响应

3 个答案: