我正在尝试创建一个自动填充特定值范围的新数组。我正在尝试使用巧妙的代码来实现这一目标。
char*到目前为止，我最好的主意如下：
Removing3.c:12:8: warning: incompatible integer to pointer conversion initializing 'char *' with an
expression of type 'char'; remove * [-Wint-conversion]
char *charTest2 = *argv[2];
^ ~~~~~~~~
Removing3.c:30:20: warning: comparison between pointer and integer ('int' and 'char *')
pw += (*pw != c);
~~~ ^ ~
2 warnings generated.
我上面的想法是，我使用散布运算符将数组Removing3.c:18:19: warning: incompatible integer to pointer conversion passing 'char' to parameter of
type 'char *'; take the address with & [-Wint-conversion]
remove_all_chars(strTest, charTest2);
^~~~~~~
&
Removing3.c:2:29: note: passing argument to parameter here
void remove_all_chars(char *, char *);
^
Removing3.c:18:28: warning: incompatible integer to pointer conversion passing 'char' to parameter of
type 'char *'; take the address with & [-Wint-conversion]
remove_all_chars(strTest, charTest2);
^~~~~~~~~
&
Removing3.c:2:37: note: passing argument to parameter here
void remove_all_chars(char *, char *);
^
Removing3.c:19:15: warning: format specifies type 'char *' but the argument has type 'char' [-Wformat]
printf("%s", strTest);
~~ ^~~~~~~
%c
Removing3.c:30:20: warning: comparison between pointer and integer ('int' and 'char *')
pw += (*pw != c);
~~~ ^ ~
4 warnings generated.
填充为一个n值的新鲜数组，这需要足够的空间来大于范围之差。然后，我使用JS // MainApplication
...
import android.content.Context;
import android.support.multidex.MultiDex;
...
public class MainApplication extends Application implements ReactApplication {
...
@Override
protected void attachBaseContext(Context base) {
super.attachBaseContext(base);
MultiDex.install(getBaseContext());
}
}
方法仅返回适合if Example given range:
1995 to 2020
Sample Output:
[1995, 1996, 1997, ..., 2020]
的三元表达式的值，然后返回范围加n的开始，所以years = [...new Array(100).filter((_, n) => (1995 + n) != 2020 ? 1995 + n : 2020)];
。
这里有什么想法吗？我正在尝试避免编写某些函数或巨型years循环，并将其保持在机智的衬里之上。感谢您的帮助！
进行编辑，以便主持人解锁问题，以便我发布解决方案。