Question

我试图做一个shell脚本来添加和删除用户到文本文件。我想使用args来比较是否删除或添加用户，但是无论我输入什么args，两个代码都可以运行，这是我的代码：

#!/bin/bash
arg1="$1"
arg2="$2"
if [ "$arg1"="add" ]; then
 if ! grep -q $arg2 "users.txt"; then
  sed -i -e 's/users:/users: \n  - '$arg2'/g' users.txt
  echo "user added: $arg2"
 else
  echo "user exists: $arg2"
 fi
fi
if [ "$arg1"="del" ]; then
 if grep -q $arg2 "users.txt"; then
  sed -i -e 's/- '$arg2'//g' users.txt
  echo "user $arg2 deleted"
 else
  echo "not found $arg2"
 fi
fi

这是我的文本文件users.txt：

users: 
  - angel
  - rick

在终端上运行sh addUser.sh add user1：

user added: user1
user user1 deleted

在终端上运行sh addUser.sh del user1：

user added: user1
user user1 deleted

结果是一样的，我该如何解决？

Answer 1

感谢@melpomene的建议问题是[ "$arg1"="add" ]中的空格将[ "$arg1"="add" ]更改为[ "$arg1" = "add" ]，即可正常使用。

#!/bin/bash
arg1="$1"
arg2="$2"
if [ "$arg1" = "add" ]; then
 if ! grep -q $arg2 "users.txt"; then
  sed -i -e 's/users:/users: \n  - '$arg2'/g' users.txt
  echo "user added: $arg2"
 else
  echo "user exists: $arg2"
 fi
fi
if [ "$arg1" = "del" ]; then
 if grep -q $arg2 "users.txt"; then
  sed -i -e 's/- '$arg2'//g' users.txt
  echo "user $arg2 deleted"
 else
  echo "not found $arg2"
 fi
fi

尝试将args与条件中的字符串进行比较时出错

1 个答案: