Question

基本上，该功能必须提示用户输入一周中某一天的前两个字母，它应该返回一周中完整的措辞日。它应该继续提示用户执行此操作，直到用户输入无效的两个字符。

def abr():
    abr = input("Enter a day abbreviation:")
    days = {Su: Sunday, Mo: Monday, Tu: Tuesday, We:Wenesday, Th: Thursday, Fr: Friday, Sa: Saturday, Su: Sunday}
    if days in abr:
        return days['']

我试图用字典来解决这个问题，但我对字典及其限制不太熟悉。

Answer 1

kojiro 是对的。你必须扭转你的条件

if abr in days:
    return days[abr]

不要忘记使用字符串作为字典键和值，因为用户输入将作为字符串返回，您将用作键。

您必须使用raw_input input is actually equivalent to an eval，这需要您的用户输入“Tu”而非Tu。

对于循环，您可以使用while循环并在检测到无效的abreviation时退出

def abr():
    abr = raw_input("Enter a day abbreviation:")
    days = {"Su": "Sunday", 
            "Mo": "Monday", 
            "Tu": "Tuesday", 
            "We": "Wednesday", 
            "Th": "Thursday", 
            "Fr": "Friday", 
            "Sa": "Saturday", 
            "Su": "Sunday"}
    if abr in days:
        return days[abr]
    return None


while(1):
    day = abr()
    if day is not None:
        print day
    else:
        break

Answer 2

你并没有太远，你只是让订单逆转了。哦，那些字典键和值都应该是字符串。

def abr():
    """Return the day given a two-letter abbreviation."""
    # Don't use the function name as a variable in the function.
    # It's just not good practice.
    abbrev = input("Enter a day abbreviation:") 
    days = {
        "Su": "Sunday",
        "Mo": "Monday",
        "Tu": "Tuesday",
        "We": "Wednesday", # [Spelling fixed]
        "Th": "Thursday",
        "Fr": "Friday",
        "Sa": "Saturday",
    } # Extra Sunday removed

    return days.get(abbrev, '')

要使循环行为发生所以它一直持续到它们点击无效的缩写，在循环中调用该函数：

while True:
    if abr() == "":
        break

或者更短一些：

while abr() != "":
    pass

Answer 3

current_designation_upper = Transformed_Data.designation.tolist（）[i] .upper（） current_designation_upper_array = re.split（“[-.!@#$%^& amp; *（）_ + =〜`：＆lt;＆gt;，/'|} {[] |]”，current_designation_upper） role_current_designation_null_removed = [如果是x，则为current_designation_upper_array中的x的x] current_designation_upper_array_with_abbrevation ='' 对于范围内的k（0，len（role_current_designation_null_removed））： temp_current_designation_upper_array_with_abbrevation = current_designation_upper_array_with_abbrevation + role_current_designation_null_removed [k] [0]

缩写词和词典

3 个答案: