Question

我的Laravel 5.6控制器中有以下代码：

$ads = Advertisement::actives();

$ports = Port::filter($filters)
    ->actives()
    ->paginate(28);

我想为每个4th端口添加一个广告。我该怎么办？

所以结果应该是：

//Collection
[
   //Port,
   //Port,
   //Port,
   //Port
   //Advertisement
   //Port
   //Port
   //Port
   //Port
   //Advertisement

   //etc...
]

Answer 1

使用chunk方法提取4个端口的块：

foreach ($ports->chunk(4) as $chunk) {
    // chunk will be a collection of four ports, pull however you need
    // then pull the next available ad
}

Answer 2

您可以像数组一样拼接到集合中。

类似...

  $ads = collect(['ad1','ad2','ad3','ad4']);

  $ports = collect([
    "port 1",
    "port 2",
    "port 3",
    "port 4",
    "port 5",
    "port 6",
    "port 7",
    "port 8",
    "port 9",
    "port10",
    "port11"
  ]);


  for($i=4; $i<=$ports->count(); $i+=5) {

    $ports->splice($i, 0, $ads->shift());

  }

  // tack on the remaining $ads at the end
  // (I didn't check if there actually are any).

  $everyone=$ports->concat($ads);

  dd($everyone);

生产...

Collection {#480 ▼
  #items: array:15 [▼
    0 => "port 1"
    1 => "port 2"
    2 => "port 3"
    3 => "port 4"
    4 => "ad1"
    5 => "port 5"
    6 => "port 6"
    7 => "port 7"
    8 => "port 8"
    9 => "ad2"
    10 => "port 9"
    11 => "port10"
    12 => "port11"
    13 => "ad3"
    14 => "ad4"
  ]  
}

Laravel切片集合

2 个答案: