我遇到了一个奇怪的错误,也没有运气去修复它。我有一些链接文件,我正在一个文件(ViewController
)中定义的一个文件(Sign.swift
)中调用函数。 Sign.swift
中的函数创建在另一个文件(GameState.swift
)中定义的输出。我不确定这有什么问题,我已经做了很多研究,甚至this answer也没有帮助。 (代码错误)。
ViewController.swift
:
import UIKit
class ViewController: UIViewController {
override func viewDidLoad() {
super.viewDidLoad()
// Do any additional setup after loading the view, typically from a nib.
}
override func didReceiveMemoryWarning() {
super.didReceiveMemoryWarning()
// Dispose of any resources that can be recreated.
}
@IBOutlet weak var computerLabel: UILabel!
@IBOutlet weak var output: UILabel!
@IBOutlet weak var rockButton: UIButton!
@IBOutlet weak var paperButton: UIButton!
@IBOutlet weak var scissorsButton: UIButton!
@IBOutlet weak var playAgain: UIButton!
@IBAction func rockButtonPressed(_ sender: UIButton) {
computerLabel.text = randomSign()
var playerChoice = Sign.rock
var output = Sign.checkInputs(playerChoice, computerLabel.text) //Error 1 is here
}
@IBAction func paperButtonPressed(_ sender: UIButton) {
}
@IBAction func scissorsButtonPressed(_ sender: UIButton) {
}
@IBAction func playAgainPressed(_ sender: UIButton) {
}
}
Sign.swift
:
import Foundation
import GameplayKit
let randomChoice = GKRandomDistribution(lowestValue: 0, highestValue: 2)
func randomSign() -> String {
let sign = randomChoice.nextInt()
if sign == 0 {
return ""
}
else if sign == 1 {
return ""
}
else {
return "✌️"
}
}
enum Sign {
case rock, paper, scissors
var emoji: String {
switch self {
case .rock:
return ""
case.paper:
return ""
case.scissors:
return "✌️"
}
}
func checkInputs(_ user: Sign, opponent: Sign) -> String {
var outcome = GameState.draw
if (opponent == .rock) {
if (emoji == "") {
outcome = .draw
}
else if (emoji == "") {
outcome = .win
}
else {
outcome = .lose
}
}
else if (opponent == .paper) {
if (emoji == "") {
outcome = .lose
}
else if (emoji == "") {
outcome = .draw
}
else {
outcome = .win
}
}
else if (opponent == .scissors) {
if (emoji == "") {
outcome = .win
}
else if (emoji == "") {
outcome = .lose
}
else {
outcome = .draw
}
}
return outcome //Error 2 is here
}
}
GameState.swift
:
import Foundation
enum GameState {
case start, win, lose, draw
var text: String {
switch self {
case.start:
return "Game started!"
case.win:
return "You win!"
case.lose:
return "You lose!"
case.draw:
return"It's a draw!"
}
}
}
两个文件都出现错误:错误1(ViewController.swift
中的注释行)显示以下错误消息:
实例成员'checkInputs'不能用于'Sign'类型;你是否 是要改用这种类型的值?
不幸的是,我不明白上述消息是什么意思,我是Swift的新手。
错误2(Sign.swift
中的注释行)显示以下消息:
无法将类型'GameState'的返回表达式转换为返回类型 “字符串”
再次,我不明白这里发生了什么。但是我的GameState.swift
文件中没有任何错误,因此这意味着所有错误都应该在ViewController.swift
和Sign.swift
中。我该如何解决这些错误?
编辑:我已经更新了代码,现在看起来像这样:
ViewController.swift
:
import UIKit
class ViewController: UIViewController {
override func viewDidLoad() {
super.viewDidLoad()
// Do any additional setup after loading the view, typically from a nib.
}
override func didReceiveMemoryWarning() {
super.didReceiveMemoryWarning()
// Dispose of any resources that can be recreated.
}
func computerChoose() {
}
@IBOutlet weak var computerLabel: UILabel!
@IBOutlet weak var output: UILabel!
@IBOutlet weak var rockButton: UIButton!
@IBOutlet weak var paperButton: UIButton!
@IBOutlet weak var scissorsButton: UIButton!
@IBOutlet weak var playAgain: UIButton!
@IBAction func rockButtonPressed(_ sender: UIButton) {
var random = randomSign()
var stringRandom = ""
switch random {
case .rock :
stringRandom = ""
case .paper:
stringRandom = ""
case .scissors:
stringRandom = "✌️"
}
var playerChoice = Sign.rock
var output = Sign.checkInputs(random)
computerLabel.text = stringRandom
}
@IBAction func paperButtonPressed(_ sender: UIButton) {
}
@IBAction func scissorsButtonPressed(_ sender: UIButton) {
}
@IBAction func playAgainPressed(_ sender: UIButton) {
}
}
Sign.swift
:
import Foundation
import GameplayKit
let randomChoice = GKRandomDistribution(lowestValue: 0, highestValue: 2)
func randomSign() -> Sign {
let sign = randomChoice.nextInt()
if sign == 0 {
return .rock
}
else if sign == 1 {
return .paper
}
else {
return .scissors
}
}
enum Sign {
case rock, paper, scissors
var emoji: String {
switch self {
case .rock:
return ""
case.paper:
return ""
case.scissors:
return "✌️"
}
}
static func checkInputs(_ opponent: Sign) -> GameState {
var outcome = GameState.draw
if (opponent == .rock) {
if (emoji == "") { //Error Emoji
outcome = .draw
}
else if (emoji == "") { //Error Emoji
outcome = .win
}
else {
outcome = .lose
}
}
else if (opponent == .paper) { //Error Emoji
if (emoji == "") {
outcome = .lose
}
else if (emoji == "") { //Error Emoji
outcome = .draw
}
else {
outcome = .win
}
}
else if (opponent == .scissors) {
if (emoji == "") { //Error Emoji
outcome = .win
}
else if (emoji == "") { //Error Emoji
outcome = .lose
}
else {
outcome = .draw
}
}
return outcome
}
}
注意:每行带有注释Error Emoji
的新错误,并显示以下错误消息:
实例成员'emoji'不能用于'Sign'类型
GameState.swift
:未更改。
在此我将不胜感激。
答案 0 :(得分:6)
如果您需要使用没有 instance 的方法,则需要将该方法声明为static
。
static func checkInputs(_ user: Sign, opponent: Sign) -> String
注意:您似乎并没有使用通过的user
。 IMO,您可以跳过询问该参数的过程,而将其用作playerChoice
的实例方法。
func checkInputs(opponent: Sign) -> String {
// Your logic
}
然后像这样使用它
playerChoice.checkInputs(opponent: randomSign())
第二个错误是因为您试图返回Sign
而不是String
的实例。您需要像@Larme所指出的那样,将返回类型更改为Sign
还是将Sign
中的outcome
转换为String
-outcome.text
?