Question

有人可以帮我吗？我已经工作了大约3天。这是关于更新记录。当我更新数据时，除“文件”外，所有数据均已更新。数据库中的“文件”变为空。

这是代码；

编辑/更新表格：

<label style="color:#e91e63">Attachement</label>
  <div class="input-group input-group-md">
        <span class="input-group-addon">
            <i class="material-icons">file_upload</i>
        </span>
        <div class="form-line">
            <input type="file" name="files" id="files" required>
        </div>
    </div>

  <!-- Edited Date -->

      <input type="hidden" name="id" id="id" />

  <input type="submit" name="insert" id="insert" value="Insert" class="btn btn-success waves-effect" />


<script>
$(document).ready(function(){
  $('#edit').click(function(){
    $('#insert').val("Insert");
    $('#insert_form')[0].reset();
  });

  $(document).on('click', '.edit_data', function(){
    var id = $(this).attr("id");
    var extension = $('#files').val().split('.').pop().toLowerCase();

    if(extension != '') {
      if(jQuery.inArray(extension, ['gif','png','jpg','jpeg', 'pdf']) == -1) {
        alert("Invalid File");
        $('#files').val('');
        return false;
      }
    }
      $.ajax({
      url:"script/fetch.php",
      method:"POST",
      data:{id:id},
      dataType:"json",
      success:function(data){
        $('#dated').val(data.dated);
        $('#ctrl_no').val(data.ctrl_no);
        $('#title').val(data.title);
        $('#category').val(data.category);
        $('#file').val(data.file);
        $('#fname').val(data.fname);
        $('#adate').val(data.adate);
        $('#createdby').val(data.createdby);
        $('#id').val(data.id);
        $('#insert').val("Update");
        $('#update_Modal').modal('show');
      }
    });
  });

  $('#insert_form').on("submit", function(event){
    event.preventDefault();
      $.ajax({
        url:"script/insert.php",
        method:"POST",
        data:$('#insert_form').serialize(),
        beforeSend:function(){
          $('#insert').val("Inserting");
        },
        success:function(data){
          $('#insert_form')[0].reset();
          $('#update_Modal').modal('hide');
          $('#refresh').html(data);
        }
      });
  });
});
</script>

从数据库中获取数据：

<?php
//fetch.php
$connect = mysqli_connect("localhost", "root", "", "record");
if(isset($_POST["id"]))
{
    $query = "SELECT * FROM dashboard WHERE id = '".$_POST["id"]."'";
    $result = mysqli_query($connect, $query);
    $row = mysqli_fetch_array($result);
    echo json_encode($row);
}
?>

更新数据。

<?php
$connect = mysqli_connect("localhost", "root", "", "record");
if(!empty($_POST))
{
  $output = '';
  $message = '';

  $ctrl_no = mysqli_real_escape_string($connect, $_POST["ctrl_no"]);
  $title = mysqli_real_escape_string($connect, $_POST["title"]);
  $category = mysqli_real_escape_string($connect, $_POST["category"]);
  $fname = mysqli_real_escape_string($connect, $_POST["fname"]);
  $adate = mysqli_real_escape_string($connect, $_POST["adate"]);
  $createdby = mysqli_real_escape_string($connect, $_POST["createdby"]);

  //file upload

  $file = '';
  if($_FILES["files"]["name"] = '')
  {
    $file = upload_file();
  }
  else
  {
    $file = $_POST["file"];
  }

  if($_POST["id"] != '')
  {
    $query = "
    UPDATE `dashboard`
    SET
    `ctrl_no`='$ctrl_no',
    `title`='$title',
    `category`='$category',
    `file`='$file',
    `fname`='$fname',
    `adate` = '$adate',
    `createdby` = '$createdby'
    WHERE `id`='".$_POST["id"]."'";
    $message = 'Data Updated.';
  }

  if(mysqli_query($connect, $query))
  {
    $output .= "<div class='alert alert-success alert-dismissible'>
    <a href='#' class='close' data-dismiss='alert' aria-label='close'>&times;</a>
    <strong>Success!</strong> $message
    </div>";
    $select_query = "SELECT * FROM `dashboard` ORDER BY `id` DESC";
    $result = mysqli_query($connect, $select_query);
    $output .= '
    <table id="dataTable" style="width:100%" class="table table-bordered table-striped table-hover">
    <thead>
    <tr>
    <th width="6%"><b>Date</b></th>
    <th width="8%"><b>Control No.</b></th>
    <th width="37%"><b>Title / Particular</b></th>
    <th width="17%"><b>Category</b></th>
    <th width="10%"><b>From /<br />End-user</b></th>
    <th width="10%"><b>File</b></th>
    <th width="7%"><b>Action</b></th>
    </tr>
    </thead>
    <tbody>
    ';
    while($row = mysqli_fetch_array($result))
    {
      $output .= '';
    }
    $output .= '</tbody></table>';
  }
  echo $output;
}

function upload_file()
{
    if(isset($_FILES["files"]))
    {
        $extension = explode('.', $_FILES['files']['name']);
        $new_name = rand() . '.' . $extension[1];
        $destination = '../file/' . $new_name;
        move_uploaded_file($_FILES['files']['tmp_name'], $destination);
        return $new_name;
    }
}
?>

<!-- Alert Success -->
<script>
window.setTimeout(function() {
  $(".alert").fadeTo(500, 0).slideUp(500, function(){
    $(this).remove();
  });
}, 5000); //timeout
</script>

唯一的问题是我无法更新文件。有任何想法吗？非常感谢您的帮助。谢谢。

Answer 1

我认为，您正在通过输入字段分配文件名。如果有人没有通过输入字段分配值，则使用了 upload_file（）方法。因此请尝试更改使用 $ _ POST [“ file”] = 来检查是否已分配名称，如果已分配，则在您的 upload_file（）中定义使用的给定其他使用的名称。

<?php
$connect = mysqli_connect("localhost", "root", "", "record");
if(!empty($_POST))
{
  $output = '';
  $message = '';

  $ctrl_no = mysqli_real_escape_string($connect, $_POST["ctrl_no"]);
  $title = mysqli_real_escape_string($connect, $_POST["title"]);
  $category = mysqli_real_escape_string($connect, $_POST["category"]);
  $fname = mysqli_real_escape_string($connect, $_POST["fname"]);
  $adate = mysqli_real_escape_string($connect, $_POST["adate"]);
  $createdby = mysqli_real_escape_string($connect, $_POST["createdby"]);

  //file upload

  $file = '';
//make the change here in if
  if($_POST["file"] = '')
  {
    $file = upload_file();
  }
  else
  {
    $file = $_POST["file"];
  }

  if($_POST["id"] != '')
  {
    $query = "
    UPDATE `dashboard`
    SET
    `ctrl_no`='$ctrl_no',
    `title`='$title',
    `category`='$category',
    `file`='$file',
    `fname`='$fname',
    `adate` = '$adate',
    `createdby` = '$createdby'
    WHERE `id`='".$_POST["id"]."'";
    $message = 'Data Updated.';
  }

  if(mysqli_query($connect, $query))
  {
    $output .= "<div class='alert alert-success alert-dismissible'>
    <a href='#' class='close' data-dismiss='alert' aria-label='close'>&times;</a>
    <strong>Success!</strong> $message
    </div>";
    $select_query = "SELECT * FROM `dashboard` ORDER BY `id` DESC";
    $result = mysqli_query($connect, $select_query);
    $output .= '
    <table id="dataTable" style="width:100%" class="table table-bordered table-striped table-hover">
    <thead>
    <tr>
    <th width="6%"><b>Date</b></th>
    <th width="8%"><b>Control No.</b></th>
    <th width="37%"><b>Title / Particular</b></th>
    <th width="17%"><b>Category</b></th>
    <th width="10%"><b>From /<br />End-user</b></th>
    <th width="10%"><b>File</b></th>
    <th width="7%"><b>Action</b></th>
    </tr>
    </thead>
    <tbody>
    ';
    while($row = mysqli_fetch_array($result))
    {
      $output .= '';
    }
    $output .= '</tbody></table>';
  }
  echo $output;
}

function upload_file()
{
    if(isset($_FILES["files"]))
    {
        $extension = explode('.', $_FILES['files']['name']);
        $new_name = rand() . '.' . $extension[1];
        $destination = '../file/' . $new_name;
        move_uploaded_file($_FILES['files']['tmp_name'], $destination);
        return $new_name;
    }
}
?>

<!-- Alert Success -->
<script>
window.setTimeout(function() {
  $(".alert").fadeTo(500, 0).slideUp(500, function(){
    $(this).remove();
  });
}, 5000); //timeout
</script>

Answer 2

确定要将文件发送到服务器端吗？如果不是，则您希望以此方式传递文件。（这是示例，我确信您将了解如何将其适合您的代码）。关键元素是formData：）

var formData = new FormData($("#formid")[0]);
$.ajax({
    url:'url',
    type: 'POST',
    data: formData,
    processData: false,
    contentType: false,
    async: false,
    success:function(response){
        if(response == '100'){
            swal({ 
              title: "Blog Added",
              text: "Blog Added Successfully",
              type: "success",
              confirmButtonText: "OK",
              showCancelButton: false,
            }, function(){
                /*location.reload();*/
                window.location.href = 'redirect link';
            });
        }else{
            toastr.error(response);
        }
    }
});

How to pass file data with AJAX and jQuery?

PHP Ajax更新/编辑记录

2 个答案: