Question

我为API创建了逻辑，在其中我使用了一个函数来检查请求是否为POST。如果没有，它将返回一个错误。

from kivy.app import App from kivy.uix.label import Label class Playground(App): def build(self): hello_world_label = Label(text="Hello World!") return hello_world_label if __name__ == "__main__": Playground().run()看起来像这样：

AuthController.php

<?php namespace App\Http\Controllers; use Illuminate\Http\Request; class AuthController extends Controller { private static function allowOneMethod($request, $allowed_method, $success_function){ $method = $request->method(); if ($method != $allowed_method){ return response()->json(['status' => 'error', 'message' => 'Method not Allowed.'], 405); } else{ $success_function(); } } public function register(Request $request) { $this->allowOneMethod($request, 'POST', function() { return response()->json(['status' => 'success', 'message' => 'It is a POST request.'], 200); }); } ...看起来像这样：

routes/api.php

但是我所看到的只是一个空白的答复。 可能是什么原因？

Answer 1

您不会返回allowOneMethod()方法

public function register(Request $request)
{
// you need to return your method value 
    return $this->allowOneMethod($request, 'POST', function() {
        return response()->json(['status' => 'success', 'message' => 'It is a POST request.'], 200);
    });

}

在Laravel中不返回JSON响应

1 个答案: