找到要充电的机器人

Question

有一个机器人想要去充电点给自己充电。 机器人从原始点（0,0）在二维平面上移动。机器人可以按照给定的步骤向上，下，左和右移动。 机器人运动的轨迹如下图所示：

$client = new \Google_Client();
$client->setAuthConfig("/pathformyclient file/client.json");
$client->addScope(\Google_Service_CloudTalentSolution::JOBS);
$client->setHttpClient(new \GuzzleHttp\Client(['verify' => false]));
$cloudTalentSolutionClient = new \Google_Service_CloudTalentSolution($client);
$projectId = "my project ID";
$parent = sprintf('projects/%s', $projectId);
$company = new \Google_Service_CloudTalentSolution_Company();
$company->setName("company name");
$company->setDisplayName("company name");
$company->setExternalId("1");
$ci = new \Google_Service_CloudTalentSolution_CreateCompanyRequest();
$ci->setCompany($company);
$com = $cloudTalentSolutionClient->projects_companies->create($projectId,ci,array('parent' => $parent));
dump($com);die

然后，程序的输出应为： 2

我的代码是

UP 5
DOWN 3
LEFT 3
RIGHT 2

我收到一个错误ValueError：没有足够的值要解压（预期2，得到1）

Answer 1

import math

pos=[0,0]

moves={"UP":[0,1],
       "DOWN":[0,-1],
       "LEFT":[-1,0],
       "RIGHT":[1,0]}

 data = list()

设置输入

 num = int(input())

 for i in range(int(num)):

    n = input()
    data.append(n)

按有效动作移动机器人

for inp in data:

    parts=inp.split()    
    mv=parts[0]
    val=parts[1]
    if mv in moves and val.isnumeric():
        pos[0] += moves[mv][0]*int(val)
        pos[1] += moves[mv][1]*int(val)

获取距离

distance=math.sqrt(pos[0]**2 + pos[1]**2)

print(round(distance))

Answer 2

pos = {
    "x": 0, 
    "y": 0
}
z=int(input())
c=0
while (c!=z):

    n = input()
    c=c+1
    if not n:
        break

    direction,steps=n.split()
    if direction == "UP":
        pos["y"] += int(steps)
    elif direction == "DOWN":
        pos["y"] -= int(steps)
    elif direction == "LEFT":
        pos["x"] -= int(steps)
    elif direction == "RIGHT":
        pos["x"] += int(steps)
print (int(round((pos["x"]**2 + pos["y"]**2)**0.5)))

Answer 3

import math
x=int(input())
dict1={"UP":0,"DOWN":0,"LEFT":0,"RIGHT":0}
for i in range(x):
    y=input().split()
    dict1[y[0].upper()]=int(y[1])
#print(dict1)

dist=math.sqrt((dict1["UP"]-dict1["DOWN"])**2 + (dict1["LEFT] - dict1["RIGHT"])**2)
dist=int(round(dist))
print(dist)

Answer 4

dict= {"x":0, "y":0}

while True:
a = input("enter your direction for the robot(UP, DOWN)etc: ")
if a=="UP":
    dict["y"]+=5    
elif a=="DOWN":
    dict["y"]-=3
elif a=="LEFT":
    dict["x"]-=3
elif a=="RIGHT":
    dict["x"]+=2
elif a=="DIST":
    d=math.sqrt(dict["x"]**2 + dict["y"]**2)
    print(d)
    break
else:
    print("invalid entry, try again")