Question

我有一个JSON文件，在其中我保持了很少的设置。以下是我的JSON文件

{

    "1":{
        "foundation_name":"Pre-Prod1",
        "api_url": "https://sys1.com"
    },
    "2":{
        "foundation_name":"Pre-Prod2",
        "api_url": "https://sys-2.com"
    },
    "3":{
        "foundation_name":"Prod1",
        "api_url": "https://sys5.com"
    }
}

我正在尝试通过迭代在屏幕上阅读此JSON和PRINT。以下是我的Powershell脚本

Function FoundationSettings {
    Write-Host 'Reading from File'
    $foundations = Get-Content ".\foundations.json" -Raw | ConvertFrom-Json
    Write-Host $foundations
    return $foundations
}

Function DisplayFoundations {
    $foundations = FoundationSettings
    foreach ($foundation in $foundations) {
        Write-Host 'here ..'
        Write-Host $foundation.foundation_name
    }

}

但是它只是以这种方式打印

Reading from File
@{1=; 2=; 3=}
here ..

如何解决？我需要解析JSON，并根据需要获得api_url数据和foundation_name

Answer 1

如果该格式不可更改，则可以使用：

frame.swaplevel(0, 1, 1).Green

     Ohio  Colorado
a 1     0         2
  2     3         5
b 1     6         8
  2     9        11

如果可以更改它，请使用JSON数组，其中array更合适：

$obj = @'
{

    "1":{
        "foundation_name":"Pre-Prod1",
        "api_url": "https://sys1.com"
    },
    "2":{
        "foundation_name":"Pre-Prod2",
        "api_url": "https://sys-2.com"
    },
    "3":{
        "foundation_name":"Prod1",
        "api_url": "https://sys5.com"
    }
}
'@ | ConvertFrom-Json

$listOfObjects = ($obj | Get-Member -MemberType NoteProperty).Name | % { $obj.$_ }

哪个给：

$listOfObjects | ConvertTo-Json

Answer 2

访问基础属性的值：

Function DisplayFoundations {
    $foundations = FoundationSettings
    foreach ($foundation in $foundations.psobject.Properties.Value) {
        Write-Host 'here ..'
        Write-Host $foundation.foundation_name
    }
}

阅读JSON并在Powershell中进行迭代

2 个答案: