Question

我正在尝试解决一个问题，该问题要求我句子并把每个辅音加倍，并在两者之间加一个'o'。

我知道可以在一行中使用if语句，但是'else'语句不起作用。

vowels = list('aeiouyäöå')
consonants = list('qwrtpsdfghjklzxcvbnm')


# if letter is a consonant then double it and out 'o' in between.
def rovarspraket(sentence):
    return ''.join([letter for letter in sentence if letter in vowels else (letter + 'o' + letter)])

print(rovarspraket('hello friend'))
# should output 'hohelollolo fofrorienondod'.

Answer 1

在条件理解中，else-part的语法有点错误：

def rovarspraket(sentence):
    return ''.join([l if l in vowels else (l + 'o' + l) for l in sentence])

甚至更好（更健壮的wrt空格）：

def rovarspraket(sentence):
    return ''.join([(l + 'o' + l) if l in consonants else l for l in sentence])

>>> print(rovarspraket('hello friend'))
hohelollolo fofrorienondod

Answer 2

空间也很重要：

return ''.join(letter if letter in vowels or letter == ' ' else (letter + 'o' + letter)for letter in sentence)

整个代码：

vowels = list('aeiouyäöå')
consonants = list('qwrtpsdfghjklzxcvbnm')


# if letter is a consonant then double it and out 'o' in between.
def rovarspraket(sentence):
    return ''.join(letter if letter in vowels or letter == ' ' else (letter + 'o' + letter)for letter in sentence)

print(rovarspraket('hello friend'))

输出：

hohelollolo fofrorienondod

如果字符串中的字母是辅音，则将字母加倍并在其之间加上“ o”，否则

2 个答案: