Question

早上好！我有一个棘手的数据集可以在Rails中使用。它是JSON对象数组的数组，每个对象具有4个属性。示例如下：

[
    [
        {
            "column_name": "ID",
            "column_id": "item_attributes#id",
            "column_value": "25295119-7113-42fe-90d5-394c7a841b31",
            "column_type": "string"
        },
        {
            "column_name": "Name",
            "column_id": "item_attributes#name",
            "column_value": "Webform submission",
            "column_type": "string"
        },
        {
            "column_name": "Current owner",
            "column_id": "item_attributes#current_owner",
            "column_value": "Joe Bloggs",
            "column_type": "string"
        },
        {
            "column_name": "State",
            "column_id": "item_attributes#state",
            "column_value": "New Task",
            "column_type": "string"
        },
        {
            "column_name": "Status",
            "column_id": "item_attributes#status",
            "column_value": "In progress",
            "column_type": "string"
        },
        {
            "column_name": "Created at",
            "column_id": "item_attributes#created_at",
            "column_value": "07/09/2018, 10:47 am",
            "column_type": "datetime"
        },
        {
            "column_name": "Updated at",
            "column_id": "item_attributes#updated_at",
            "column_value": "07/09/2018, 10:47 am",
            "column_type": "datetime"
        },
        {
            "column_name": "Task reviewer",
            "column_id": "item_participant_attributes#90a76abe-028f-45bc-8390-433bc39ba02e",
            "column_value": "Jane Bloggs",
            "column_type": "string"
        },
        {
            "column_name": "Task owner",
            "column_id": "item_participant_attributes#5bce3a02-07bf-4353-9f3d-2cc60f787584",
            "column_value": "Jack blogs",
            "column_type": "string"
        },
        {
            "column_name": "Make a list of your weekly tasks. Update status of this object to complete when it's complete.",
            "column_id": "element_attributes#533e26d8-c313-4d94-ab99-37263b0aa4ee",
            "column_value": null,
            "column_type": "string"
        },
        {
            "column_name": "Set target end date (choose Friday for end of this week)",
            "column_id": "element_attributes#6eeddd67-e1de-40c3-b220-197ddf554241",
            "column_value": null,
            "column_type": "datetime"
        },
        {
            "column_name": "Reviewer comments (optional)",
            "column_id": "element_attributes#3923358c-85f0-444b-9287-4738d9148eb9",
            "column_value": null,
            "column_type": "string"
        }
    ], 
    [...]
]

我有一个名为ReportTemplateColumn的模型，该模型定义了每个项目所需的sort_priority和sort_direction以及相关的column_id。

我需要遍历ReportTemplateColumns并将其排序方向按优先级顺序应用于上述数据集。

例如，我知道我需要按column_id = item_attributes#name按desc重新排序数据集。数组数组需要根据column_value值更改顺序。

我的尝试

  def set_sorted_data(data)
    @new_data = data
    self.report_template.report_template_columns.where('sort_priority != ?', 1000).order(:sort_priority).each do |report_template_column|
      @new_data = @new_data.sort_by { |x| x[0]["column_value"] }
    end
    return @new_data
  end

Answer 1

我认为.sort_by { |x| x[0]["column_value"] }是主要问题，例如，如果您遇到类似问题。

f = [[{'a' => 4}, {'a' => 2}]]
# => [[{"a"=>4}, {"a"=>2}]]
f.sort_by{|d| d[0]['a']}
# => [[{"a"=>4}, {"a"=>2}]], won't change anything
f.first.sort_by{|d| d['a'] } # first represent the [0] here
# => [{"a"=>2}, {"a"=>4}], This gonna work

使用您的方法时出现了问题，即您正在对外部数组进行排序，使得像这样的{ |x| x[0]["column_value"] }时，我相信ruby试图通过对内部数组{{1}进行排序来对(outer array)进行排序}称为(which is one)的某个属性，但是如上面的示例所示，指定您对内部数组的操作会影响内部数组，希望它能与您一起使用。

您可以使用'column_value'对它进行就地排序。

Answer 2

下面是一个可行的实现，可能不是最佳选择，但可行：

  def set_sorted_data(data)
    @new_data = data
    self.report_template.report_template_columns.where('sort_priority != ?', 1000).order(:sort_priority).reverse.each_with_index do |report_template_column|
      @new_data[0].each_with_index do |item_row_datum, index|
        if item_row_datum[:column_id] == report_template_column.column_id
          @index = index
        end
      end
      if report_template_column.column_type == 'number'
        @new_data.sort_by! { |item_row_datum| item_row_datum[@index][:column_value].to_i }
      elsif report_template_column.column_type == 'datetime'
        @new_data.sort_by! { |item_row_datum| item_row_datum[@index][:column_value].to_date }
      else
        @new_data.sort_by! { |item_row_datum| item_row_datum[@index][:column_value].to_s }
      end
      if report_template_column.sort_direction == 'desc'
        @new_data = @new_data.reverse
      end
    end
    return @new_data
  end

如何在Ruby中对JSON对象的嵌套数组进行排序？

2 个答案: